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telo118 [61]
3 years ago
6

Why is the nucleus of an atom dense​

Physics
1 answer:
Inessa [10]3 years ago
7 0

Explanation:

The nucleus of an atom is dense because it contains more of particles in a very little space.

The nucleus is the center of an atom made up of the protons and neutrons.

Atomic nucleus is very small compared to the size of the atom.

 Density is function of mass and volume.

Mass is the amount of matter in a substance.

Volume is the space occupied by a substance.

    The more the mass the more the density.

Since protons and neutron are massive bodies occupying a small space, they make the nucleus very dense.

learn more:

Density brainly.com/question/5055270

#learnwithBrainly

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Quantum mechanics can be thought of as a ...
Mekhanik [1.2K]

Answer:

c. probablistic view of nature.

Explanation:

According to the problem of particle in a box in one dimension. If the particle energy E is taken less than the height of the barrier V.

Then with the help of classical mechanics it can be prove that the particle can not cross the barrier but according to the quantum mechanics, there is a small but a finite probability to cross the barrier.

Therefore by the above discussion it can be concluded that quantum mechanics can be thought as a probablistic view of nature.

7 0
3 years ago
an automobile is traveling 65km/h the brakes decelerate it at a rate of -6.0 m/s^2 how long will it take to stop the car?
joja [24]

Explanation:

It is given that,

Initial speed of the automobile, u = 65 km/hr =

Final speed of the automobile, v = 0

Deceleration of the automobile, a=-6\ m/s^2

We need to find the distance covered by the car as it comes to rest. It can be calculated using third equation of motion as :

v^2-u^2=2ax

a=\dfrac{v^2-u^2}{2x}

a=\dfrac{0-(18.05)^2}{2\times (-6)}

a=27.15\ m/s^2

So, the acceleration of the car is 27.15\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. Wha
Snowcat [4.5K]

Answer:

176.4 m

Explanation:

U = 0, t = 6s, g = 9.8 m/s^2

Use second equation of motion

H = ut + 1/2 gt^2

H = 0 + 0.5 × 9.8 × 6 × 6

H = 176.4 m

It is the displacement from the point of dropping of object.

3 0
3 years ago
When you hold your hands at your sides, you may have noticed that the veins sometimes bulge--the height difference between your
hodyreva [135]

To solve this problem it is necessary to use the concepts related to pressure and pressure, absolute and atmospheric.

Average arterial pressure in the hands,

P = 100mmHg+ h*\rho_{blood}g

Where,

P = Pressure

h = height (at this case the length of the arm)

Replacing with our values

P = 100mm(Hg)+(600mm)(\frac{\rho_{blood}}{\rho_{mercury}})(Hg)

P = 100mmHg+600*\frac{1060}{13600}mmHg

P = 100mmHg+46.765mmHg

P = 146.765mmHg

Where,

\rho_{blood} = 1060Kg/m^3

\rho_{mercury}=13600Kg/m^3

Therefore the pressure is 146.765mmHg

7 0
3 years ago
Your shopping cart has mass of 65 kg. In order of accelerate the shopping cart down an aisle at 0.3 m/sec^2, what force would yo
aleksklad [387]
Fnet = m x a
= 65kg x 0.3m/s^2
= 19.5N
This is assuming that there is no friction or other external forces!
4 0
3 years ago
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