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svlad2 [7]
3 years ago
13

What determines the amount of energy an electron has?

Chemistry
1 answer:
Natalka [10]3 years ago
8 0

Answer:

The energy of an electron in many–electron atom is determined by both principal quantum number (n) and azimuthal quantum number (l)

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To prevent poisoning, what three items should NEVER be taken into the lab?
Roman55 [17]

The answer of this answer is given in the attached file

Download pdf
7 0
3 years ago
A compound is found to have an empirical formula of CH2O. If its molecular mass is 60.0 g/mol, what is its molecular formula?
denpristay [2]
The empirical formula CH₂O has a mass [(12 × 1) + (1 × 2) + (16 × 1)] = 30 g/mol

If the empirical formula is 30 g/mol,
and the molecular formula is 60 g/mol

Then the multiple is = 60 g/mol ÷ 30 g/mol 
                                = 2

Therefor the molecular formula is 2(CH₂O) = C₂H₄O₂   (OPTION 2)
8 0
3 years ago
A cyanide solution with avolume of 12.73 mL was treated with 25.00 mL of Ni2+solution (containing
natima [27]

Answer:

The molarity of this solution is 0,09254M

Explanation:

The concentration of the Ni²⁺ solution is:

Ni²⁺ + EDTA⁴⁻ → Ni(EDTA)²⁻

0,03935L × 0,01307M = 5,143x10⁻⁴ moles Ni²⁺ ÷ 0,03010L =<em>0,01709M Ni²⁺</em>

25,00 mL of this solution contain:

0,01709M × 0,02500L = 4,2716x10⁻⁴ moles of Ni²⁺

The moles of Ni²⁺ that are in excess and react with EDTA⁴⁻ are:

0,01015L × 0,01307M = 1,3266x10⁻⁴ moles of Ni²⁺

Thus, moles of Ni²⁺ that react with CN⁻ are:

4,2716x10⁻⁴ - 1,3266x10⁻⁴ = 2,9450x10⁻⁴ moles of Ni²⁺

For the reaction:

4CN⁻ + Ni²⁺ → Ni(CN)₄²⁻

Four moles of CN⁻ react with 1 mole of Ni²⁺:

2,9450x10⁻⁴ moles of Ni²⁺ × \frac{4 mol CN^-}{1 molNi^{2+}} = <em>1,178x10⁻³ moles of CN⁻</em>

As the volume of cyanide solution is 12,73mL. The molarity of this solution is:

<em>1,178x10⁻³ moles of CN⁻ ÷ 0,01273L = </em><em>0,09254M</em>

I hope it helps!

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