Answer:
Empirical formula of compound is C₄H₈O
Explanation:
Given data:
Mass of compound = 5.60 g
Mass of CO₂ = 13.7 g
Mass of H₂O = 5.60 g
Empirical formula of compound = ?
Solution:
Percentage of C:
13.7 g/5.60 g × 12/44× 100
2.45×0.273× 100 = 66.9%
Percentage of H:
5.60 g/ 5.60 g × 2.016/18 × 100
11.2%
Percentage of O:
(66.9% + 11.2%) - 100 = 21.9%
Grams atom of C , H, O
66.9/12 = 5.6
11.2 / 1.008 = 11.11
21.9 / 16 = 1.4
Atomic ratio:
C : H : O
5.6/1.4 : 11.11/1.4 : 1.4/1.4
4 : 8 : 1
Empirical formula:
C₄H₈O
A drilling method used to extract petroleum or oil from deep in the earth. This process occurs when cracks in and below the earths surface are opened and widened by injecting water,chemicals and sand at high pressure. Sorry if this doesn’t help much I tried :)
The blanks are left to right:
(But first I want brainliest so I can get a better rank)
solid,liquid ---> solid,liquid,gas.
Answer:
0.268 L
Explanation:
concentration is the number of moles of solute in 1 L of solution
number of moles of KCl - 5.0 g / 74.5 g/mol = 0.067 mol
the concentration of the solution to be prepared - 0.25 mol/L
concentration = number of moles of KCl / volume of solution
substituting the values in the equation
0.25 mol/L = 0.067 mol / V
V = 0.268 L
solution should be diluted to 268 mL to make a 0.25 M solution
