Think about how particles are arranged inside atoms. Please name and describe those three particles, and describe how the partic
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Answer:
A) 8.00 mol NH₃
B) 137 g NH₃
C) 2.30 g H₂
D) 1.53 x 10²⁰ molecules NH₃
Explanation:
Let us consider the balanced equation:
N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)
Part A
3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:
Part B:
1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:
Part C:
According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:
Part D:
6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:
Answer : The mass of required is, 166.4 grams.
Explanation :
First we have to calculate the moles of nitrogen gas.
Using ideal gas equation:
where,
P = Pressure of gas = 1.00 atm
V = Volume of gas = 113 L
n = number of moles = ?
R = Gas constant =
T = Temperature of gas =
Putting values in above equation, we get:
Now we have to calculate the moles of sodium azide.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 3 mole of produced from 2 mole of
So, 3.84 moles of produced from
moles of
Now we have to calculate the mass of
Molar mass of = 65 g/mole
Therefore, the mass of required is, 166.4 grams.