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never [62]
3 years ago
14

Compared to freezing point and boiling point of water at 1 atmosphere, a solution of salt and water at 2 atmosphere has a ______

_____.
Chemistry
1 answer:
FinnZ [79.3K]3 years ago
6 0

Answer: What occurs when NaCl(s) is added to water. (1) ... (2) The boiling point of the solution increases, and the freezing point of the solution increases. ... (1) higher freezing point and a lower boiling point than water (2) ... Jan 2007-19 Compared to a 2.0 M aqueous solution of NaCl at 1 atmosphere, a 3.0 M aqueous ...

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Explanation:

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According to Table I, which equation represents a change resulting in the greatest quantity of energy released?
love history [14]
The answer is 3. The releasing of energy means exothermic reaction. So the ΔH should be negative. And the greatest quantity of energy released means that the greatest number. So according to the table I, the answer is 3.
8 0
3 years ago
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How many bananas are equal to 7.50 moles of bananas?​
Veseljchak [2.6K]

Answer:

4.52×10^24

Explanation:

N = n × Na

where; N = no. of bananas

n = no. of moles

Na = Avogadro's constant

Which is 6.02×10^23

N = 7.5 × 6.02×10^23

N =4.515×10^24

7 0
3 years ago
When a pendulum swings, if it is not continuously pushed it will not stop eventually because some of its energy is changed into.
Vladimir79 [104]
Well, there is kinetic energy when the object is in motion. But it will stop eventually because that energy is converted into thermal energy, or heat.
7 0
3 years ago
Calculate the number of grams of oxygen required to convert 48.0 g of glucose to co2 and h2o.
worty [1.4K]

I believe that the balanced chemical reaction is:

C6H12O6 + 6 O2 → 6 CO2 + 6 H2O 

 

So the number of grams of oxygen required is:

mass O2 required = 48 g C6H12O6 * (1 mole C6H12O6 / 180.16 g) * (6 mole O2 / 1 mole C6H12O6) * (32 grams O2 / 1 mole)

<span>mass O2 required = 51.15 grams</span>

4 0
3 years ago
The density of ethanol is 0.789 g/mL. If you need 460.0 g of ethanol for an experiment, how many milliliters would you measure o
4vir4ik [10]

Answer:

The volume is 583.02 mL

Explanation:

Given that the density is:-

\rho=0.789\ g/mL

The mass, m=460.0\ g

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

Using the above expression to calculate the volume as:-

V=\frac{m}{\rho}

Applying the values to calculate the volume as:-

V=\frac{460.0\ g}{0.789\ g/mL}=583.02\ mL

<u>The volume is 583.02 mL.</u>

3 0
3 years ago
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