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Tomtit [17]
3 years ago
12

2. (05.02 MC)

Chemistry
1 answer:
iVinArrow [24]3 years ago
5 0

Solution :

We know, molecular mass of NH₃ is , M = 17 g/mol .

Number of moles of NH₃ in 7.2 × 10²⁴ are :

n = \dfrac{7.2 \times 10^{24}}{6.022 \times 10^{23}}\\\\n = 11.96\ moles

So, mass of NH₃ present in 11.96 moles is :

m = 11.96 × 17 gram

m = 203.32 gram

Hence, this is the required solution.

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Hat volume of a 0.540 M NaOH solution contains 12.5 g NaOH
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Answer:

At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.

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