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vlada-n [284]
3 years ago
13

Periodic table the first row of elements fits in the period blank after the element blank the second row of elements fits in per

iod blank
Chemistry
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

The first row fits in period 2

The second row fits in period 3

Explanation:

Elements arranged vertically in the periodic table in groups that share similar chemical properties.

Elements are also organized horizontally in rows or periods

The length of each period is determined by the number of electrons that can occupy the sublevels being filled in that period.

You might be interested in
Hydrogen boils at 20k. what is the boiling point of hydrogen on the celsius scale
Dimas [21]

Celsius scale is related to kelvin scale by the following equation,

⁰C = K-273

°C = K-273  

So as here temperature is given in kelvin, so it can be converted into celsius as follows:

So 20 K = 20K-273 °C  

= -253 °C .

So, the 20 K temperature equals to -253 °C.

So , -253 °C is equals to  20 K or 20 K temperature equals to -253 °C.

4 0
3 years ago
All of the following are part of the electromagnetic spectrum but
Lelechka [254]
Your answer is radio waves
6 0
3 years ago
Which material is likely to slow the flow of electric charges the most? Explain
vesna_86 [32]

Answer:

The material that would most likely slow the flow of electricity is plastic.

Explanation:

Plastic is a conductor. A conductor is something that stop or slows down the flow of electricity.

4 0
2 years ago
How much potassium chloride is needed to make 0.500 m solution with 1.50 L of water?
Andrew [12]

Answer:

55.9 g KCl.

Explanation:

Hello there!

In this case, according to the definition of molality for the 0.500-molar solution, we need to divide the moles of solute (potassium chloride) over the kilograms of solvent as shown below:

m=\frac{mol}{kilograms}

Thus, solving for the moles of solute, we obtain:

mol=m*kilograms

Since the density of water is 1 kg/L, we obtain the following moles:

mol=0.500mol/kg*1.50kg\\\\mol=0.75mol

Next, since the molar mass of KCl is 74.5513 g/mol, the mass would be:

0.75mol*\frac{74.5513g}{1mol}\\\\55.9g \ KCl

Regards!

4 0
3 years ago
What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?
Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>

m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.

<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>

<em>∴ The freezing point of the solution is - 4.39 °C.</em>

6 0
3 years ago
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