Answer:
pH of the solution after addition of 8 ml 0,296 molar HCl = 7.94
Explanation:
In this case buffer exist between hypochlorous acid HClO is a weak acid and its conjugate base hypochlorite ion ClO⁻ which are deliver to the solution by NaOCl ( sodium hypochlorite ).
The salt is completely dissociate
[NaOCl] = [ClO⁻]
Using Henderson equation to find pH of this buffer
pH = pKa + log
or, = 7.53 + log
or, = 7.53 + 0.4
or, = 7.94
Explanation:
The sulfonation of the naphthalene yield 2 products under different conditions:
<u>When the reaction is carried at 80 °C, 1-naphthalenesulfonic acid is the major product because it is kinetically favoured product as arenium ion formed in the transition state corresponding to 1-naphthalenesulfonic acid is more stable due to better resonance stabilization. </u>
<u>When the reaction is carried at 160 °C, 2-naphthalenesulfonic acid is the major product as it is more stable than 1-naphthalenesulfonic acid because of steric interaction of the sulfonic acid group in 1-position and the hydrogen in 8-position.</u>
The products are shown in image below.
