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3 years ago

The figure is the net for a rectangular prism.

Mathematics

1 answer:

Montano1993 [528]3 years ago

6 0

The answer is 174

Hope This Helps ^_^

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Need help with all them plz and thank you and may god bless you

Elena-2011 [213]

1) Flounder
2) The second option(its blurry)
3) 4
4) 1
5) I think 52(its blurry)
6) 12
7) 2 1/3
8) 51
9) 5/6
10) 38
11) 40
12) The error is the negative sign because when finding absolute value the answer can never be zero since absolute value is the how far the thing is from zero, unless the negative sign is outside the absolute value lines.
13) >
14) =
15) <
16) >
17) a: your boat (18) friends boat (23).
b: your friends boat is farther behind the winning boat.
18) -2, 0, 1, 3, 5
19) -5, -3, 1, 3, 5
20) Always True
21) Never True
22) Sometimes

P.S You should give more points for this and you should get tutoring or you won't learn how to do this its pretty easy just a suggestion not calling you dumb or anything.

4 0

3 years ago

M and m Please find quick

Lady_Fox [76]

Answer:

wELL YOU WANT TO GRAB SOME M AND MS AND EAT THEM

Step-by-step explanation:

4 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

Solving the trigonometry functions

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

Help plz show work plz

Feliz [49]

Answer: c) 286.5 in²

Step-by-step explanation:

S.A.= 2π r · h

= 2π (7.3/2) · 12.5

= 2π (3.65) (12.5)

= 286.5

6 0

3 years ago

Tiffany arrived at the airport at 3:50PM. Her flight was supposed to leave at 5:15PM, but it was delayed for 2 hours. How long w

Wittaler [7]

Answer: 3 hours and 25 minutes

Step-by-step explanation:

8 0

3 years ago