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2 years ago

The figure is the net for a rectangular prism.

Mathematics

1 answer:

Montano1993 [528]2 years ago

6 0

The answer is 174

Hope This Helps ^_^

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Rachna purchases a plant that is 6 inches tall. Every week the plant grows an additional 0.6 inches. Rachna draws a graph of the

aleksklad [387]

Answer:

0.6

Step-by-step explanation:

Slope is the change in y divided by change in x.

x is weeks

y is height

We know plant grows 0.6 inches every week. This means per 1 week [change in x], the plant grows 0.6 inches [change in y]

Slope = 0.6/1 = 0.6

0.6 is the slope of the function

5 0

2 years ago

Find the pressure exerted by a force of 240 N on an area of 30 cm2. Find the answer in SI unit

NeTakaya

Answer:

Pressure is 80,000 pascals.

Step-by-step explanation:

Area:

$= { \bf{ 30 \times {10}^{ - 4} \: {m}^{2} }}$

Pressure:

${ \bf{pressure = \frac{force}{area} }} \\ \\ { \tt{ = \frac{240}{30 \times {10}^{ - 4} } }} \\ = { \tt{80000 \: pascals}}$

4 0

2 years ago

1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is $(2x+10)^\circ$ , so the measure of arc DF is

$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

The inscribed angle theorem tells us that the central angle subtended by arc DF, $\angle DOF$ , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

$m\angle DOF=2m\angle OEF=64^\circ$

so the measure of arc DF is also 64 degrees. So we have

$170-2x=64\implies106=2x\implies\boxed{x=53}$

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$