Answer:
My answer is 7.2 km
Explanation:
When Stephen goes to the south and then to the east, he is drawing a right triangle, where the 4 km and 6 km sides are the cathetus of a right triangle.
Then we use the Pithagorean theorem to solve this problem. We need to find the hypotenuse.
c² = a² + b²
c² = 4² + 6²
c² = 16 + 36
c² = 52
c = 7.2 km
This is Newton's second law of motion.
It states that Force exerted on a moving object is directly proportional to its product of mass and acceleration.
i.e Force(F) = Mass(M) × Acceleration(A)
Because Force is constant here, reducing the weight of the body the force is applied to consequently reduces its mass.
If mass is reduced, the body's acceleration increases hence increasing its speed.
That is why the 40N dumbbell move faster.
Answer:
1.000153 T
Explanation:
The energy change ΔE = hc(1/λb - 1/λa)
= 6.626069 ✕ 10⁻³⁴ J · s 2.997925 × 10⁸ m/s(1/6.544750 × 10⁻⁷ m - 1/6.544550 × 10⁻⁷ m)
= 19.864457907 × 10⁻²⁶(1527942.2438 - 1527988.9374) = 19.864457907 × 10⁻²⁶(-46.6936)
= 927.543052 × 10⁻²⁶
= -9.275431× 10⁻²⁴ J.
This energy change ΔE = 2μBB. So the magnetic field, B is
B = ΔE/2μB where μB = 9.274009 ✕ 10⁻²⁴ J/T
B = -9.275431× 10⁻²⁴ J/9.274009 ✕ 10⁻²⁴ J/T = -1.000153 T
The magnitude of the magnetic field B = 1.000153 T
Answer:
F = -11199.63 N
Explanation:
given,
mass of the brick = 12 Kg
height of the fall, h = 1.9 m
thickness of the carpet = 2 cm = 0.02 m
average force = ?
velocity of brick just before hitting mat


v = 6.11 m/s
velocity of brick just before hitting ground= 6.11 m/s
final velocity = 0 m/s
using equation of motion for acceleration calculation.
v² = u² + 2 a s
0² = 6.11² + 2x a x 0.02

a =-933.3025 m/s²
now, average force is equal to
F = m a
F = 12 x (-933.3025)
F = -11199.63 N
negative sign represent the decelerating force.
Answer:
0.381 m
Explanation:
Distance traveled S is found by

Where S is distance traveled, u is initial velocity, t is time, a is acceleration
Since we acceleration a is given as 60g, where g is gravitational constant of 9.81 then a=60*9.81=588.6
The initial velocity u is zero hence ut=0
Substituting a with 588.6, t with 36 ms
S=0.381 m