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erik [133]
2 years ago
14

Technician A says that in a series circuit, if one light goes out, the rest of the lights stay on. Technician B says that in a p

arallel circuit, if one light goes out, the rest of the lights stay on. Which technician is correct?
Physics
1 answer:
vivado [14]2 years ago
6 0

Answer:

Explanation:

Technician A is incorrect as in series circuit the current is the same for all the resistors and if one bulb fails in the path then the circuit is incomplete and therefore no flow of current.

Technician B is correct as in parallel circuit there are multiple paths for current through which it can pass and malfunctioning of one resistor does not affect the other.      

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An elastic conducting material is stretched into a circular loop of 11.2 cm radius. It is placed with its plane perpendicular to
anygoal [31]

Answer:

0.426 volts

Explanation:

It is given that,

The radius of a circular loop, r = 11.2 cm = 0.112 m

An elastic conducting material is stretched into a circular loop.

It is placed with its plane perpendicular to a uniform 0.880 T magnetic field.

The radius of the loop starts to shrink at an instantaneous rate of 68.8 cm/s, dr/dt = 0.688 m/s

We need to find the emf induced in the loop at that instant.

\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{d}{dt}(BA)\\\\=\dfrac{d}{dt}(\pi r^2 B)\\\\=\pi B\dfrac{d}{dt}(r^2)\\\\=2\pi B r\dfrac{dr}{dt}\\\\=2\pi \times 0.88\times 0.112\times 0.688\\\\=0.426\ V

So, the magnitude of induced emf is 0.426 volts.

4 0
2 years ago
A shot putter heaves a 7.26kg shot with final velocity of 7.50m/s what is kinetic energy?
ivanzaharov [21]

Answer: KE=.5mv^2

KE=.5(7.62)(7.5)^2

KE=.5(7.62)(56.25)

KE=.5(428.625)

KE=214.3125 J of KE

Explanation:

8 0
2 years ago
A wagon wheel consists of 8 spokes of uniform diameter, each of mass ms and length L cm. The outer ring has a mass mring. What i
just olya [345]

Answer:

The moment of inertial of the wheel,  I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2

Explanation:

Given;

8 spokes of uniform diameter

mass of each spoke, = M_s

length of each spoke, = L

mass of outer ring, = M_r

The moment of inertial of the wheel will be calculated as;

I = 8I_{spoke} + I_{ring}

where;

I_{spoke is the moment of inertia of each spoke

I_{ring is the moment of inertia of the rim

Moment of inertia of each spoke =\frac{1}{3}M_sL^2

Moment of inertial of the wheel

I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2

6 0
2 years ago
A) explain how the data matches each line on the graph (give name and line letter for each)
stepladder [879]
The answer you have is right good job 12
3 0
2 years ago
If v=10v, what value of R would limit l to 10 mA? (if you have 10 volts, what resistance would be needed to limit the current to
777dan777 [17]

r=v/i =10/0.01=1000ohms B

7 0
3 years ago
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