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3 years ago

7

What element is undergoing reduction (if any) in the following reaction?

1 answer:

expeople1 [14]3 years ago

6 0

The correct answer is Ag.

Ag is the element that is undergoing reduction in the given reaction. Reduction refers to a gain of electrons and a decrease in oxidation number. So based in all the given reaction, Ag is the element that is undergoing reduction. I hope this answer helped you.

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How many molecules are in 41.8 g of sulfuric acid

Anton [14]

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× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

$Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol$

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

$\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules$

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

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1 year ago