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3 years ago

What the volume is.

Chemistry

1 answer:

alekssr [168]3 years ago

4 0

The molar mass of NO₂ is 46.0 g/mol

The molar mass of Pb (NO₃)₂ is 331.2 g/mol

First there is a need to find the number of moles of NO₂ via the stoichiometry of reaction:

2Pb(NO₃)₂ → 2PbO (s) + 4NO₂ (g) + 02 (g)

2 × 331.2 g = 4 × 46.0 g

16.87 g = x (mass of NO₂)

mass of NO₂ = 16.87 × 4 × 46 / 2 × 331.2

mass of NO₂ = 3104.08 / 662.4

mass of NO₂ = 4.686 g of NO₂

Now the number of moles are:

1 mole NO₂ = 46.0 g

x moles of NO₂ = 4.686 g

4.686 × 1 / 46.0 = 0.101 moles of NO₂

1 mole = 22.4 L (at STP)

0.101 moles of NO₂ = 0.101 × 22.4 / 1

= 2.26 L

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What is below the Ecosystem .

Zigmanuir [339]

Below the ecosystem is soil, granted, and bedrock. however for the ocean ecosystem has sand below it.

8 0

4 years ago

What are the charges of families 1, 2, & 13 (boron family) if/when they become Ions

Natalka [10]

Answer:

Explanation:

Group one elements are alkali metals. All alkali metal have one valance electron. They loses their one valance electron and from cation with charge of +1.

Charges on group one.

Hydrogen = +1

Lithium = +1

Sodium = +1

Potassium = +1

Rubidium = +1

Cesium = +1

Francium = +1

Group two elements are alkaline earth metals. All alkaline earth metal have two valance electron. They loses their two valance electron and from cation with charge of +2.

Charges on group two.

Beryllium = +2

Magnesium = +2

Calcium = +2

Strontium = +2

Barium= +2

Radium = +2

Group 13 elements are boron family. All elements have three valance electrons. They loses their three valance electron and from cation with charge of +3.

Charges on group 13.

Boron = +3

Aluminium = +3

Gallium = +3

Indium = +3

Thallium= +3

Group 13 elements are also shows +1 charge by losing one valance electron.

8 0

4 years ago

Which alkyl halide reacts fastest with trimethylamine in sn2 reaction?

Ede4ka [16]

Structure V reacts fastest with trimethylamine in SN2 reaction. Owing to less steric crowding in the transition state and ease of cleavage of the R - I bond

The question is incomplete, the complete question is shown in the image attache to this answer.

SN2 reaction is a type of nucleophilic reaction in which the nucleophile attacks the substrate from the reverse side. This is a synchronous reaction because the leaving group departs as the entering group attacks simultaneously in a hypervalent transition state.

SN2 reaction is favored by structure V owing to less steric crowding in the transition state and the easy of cleavage of the R - I bond. Hence, structure V reacts fastest with trimethylamine in SN2 reaction.

Learn more: brainly.com/question/13721588

7 0

3 years ago

The dosage for an antibiotic is prescribed at 8.0 mg per kilogram of body weight taken it twice daily for 2 weeks what total mas

krek1111 [17]

Answer:

18.2784 g

Explanation:

First we convert 180 lb to kg:

1 lb = 0.453 kg

180 lb * 0.453 kg / lb = 81.6 kg

Now we calculate the mass of antibiotic taken in one day:

8.0 mg/kg * 81.6 kg = 652.8 mg

Given that it is taken twice daily, in one day the person would take (652.8 * 2) 1305.6 mg. In grams that mass would be:

1305.6 mg / 1000 = 1.3056 g

Finally we multiply those 1.3056 daily grams by the 14 days in two weeks:

(1.3056 g) * 14 = 18.2784 g

7 0

3 years ago

If 13.2 kg of Al 2 O 3 ( s ) , 50.4 kg of NaOH ( l ) , and 50.4 kg of HF ( g ) react completely, how many kilograms of cryolite

Elodia [21]

Answer : The mass of cryolite produced will be, 54.38 kg

Solution : Given,

Mass of $Al_2O_3$ = 13.2 kg = 13200 g

Mass of $NaOH$ = 50.4 kg = 50400 g

Mass of $HF$ = 50.4 kg = 50400 g

Molar mass of $Al_2O_3$ = 101.9 g/mole

Molar mass of $NaOH$ = 40 g/mole

Molar mass of $HF$ = 20 g/mole

Molar mass of $Na_3AlF_6$ = 209.9 g/mole

First we have to calculate the moles of $Al_2O_3,NaOH$ and $HF$ .

$\text{ Moles of }Al_2O_3=\frac{\text{ Mass of }Al_2O_3}{\text{ Molar mass of }Al_2O_3}=\frac{13200g}{101.9g/mole}=129.54moles$

$\text{ Moles of }NaOH=\frac{\text{ Mass of }NaOH}{\text{ Molar mass of }NaOH}=\frac{50400g}{40g/mole}=1260moles$

$\text{ Moles of }HF=\frac{\text{ Mass of }HF}{\text{ Molar mass of }HF}=\frac{50400g}{20g/mole}=2520moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Al_2O_3+6NaOH+12HF\rightarrow 2Na_3AlF_6+9H_2O$

From the balanced reaction we conclude that

The mole ratio of $Al_2O_3,NaOH$ and $HF$ is, 1 : 6 : 12

And, the ratio of given moles of $Al_2O_3,NaOH$ and $HF$ is, 129.54 : 1260 : 2520

From this we conclude that, $NaOH,HF$ is an excess reagent because the given moles are greater than the required moles and $Al_2O_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Na_3AlF_6$

From the reaction, we conclude that

As, 1 mole of $Al_2O_3$ react to give 2 mole of $Na_3AlF_6$

So, 129.54 moles of $Al_2O_3$ react to give $129.54\times 2=259.08$ moles of $Na_3AlF_6$

Now we have to calculate the mass of $Na_3AlF_6$

$\text{ Mass of }Na_3AlF_6=\text{ Moles of }Na_3AlF_6\times \text{ Molar mass of }Na_3AlF_6$

$\text{ Mass of }Na_3AlF_6=(259.08moles)\times (209.9g/mole)=54380.892g=54.38kg$

Thus, the mass of cryolite produced will be, 54.38 kg

5 0

3 years ago