Answer: Option (4) is the correct answer.
Explanation:
It is known that density is mass divided by volume.
Mathematically, Density = 
Since, density is directly proportional to mass. So, more is the mass of an element more will be its density.
Mass of magnesium is 24.305 g/mol.
Mass of barium is 137.327 g/mol.
Mass of beryllium is 9.012 g/mol
Mass of radium is 226 g/mol.
Hence, radium has more mass therefore it will have the greatest density at STP.
Answer:
A. 15859.2 L or 15900 L
B. 0.629 mol
Explanation:
At STP, one mole is equal to approximately 22.4 L
L or mL is volume, so you are attempting to solve for L or mL.
A.
708 mol x (22.4 L/1 mol) = 15859.2 L (w/ significant figures included - 15900 L)
B.
(14.1 L) x (1 mole/ 22.4 L) = 0.629 mol.
Answer:
1.09 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>
<em />
The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:
100 g × (1 mol/255.43 g) = 0.391 mol
0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:
0.391 mol × (1 L/0.360 mol) = 1.09 L
1.A two face mixture is a type of mixture in which the components of the mixture are in different states of matter. A good example of a two face mixture is carbonated soft drink. Carbonated soft drink is a mixture of carbon dioxide [which is a gas] and water [which is a liquid]. Another example of a two face mixture is the the mixture of iodine and sodium solution.
2. To separate the mixture of iodine and sodium solution the best separation method to use is sublimation.
Sublimation process is used to separate mixtures in which one of the component of the mixture can translate from the solid state to the gaseous state without passing through the liquid state. An example of a solid which can sublime is iodine.
The sublimation process involves heating the mixture. On heating, the sublime solid will turn to vapour and escape from the mixture leaving behind the other component. The sublime component will be regained when it cools down.
