Question

What the volume is.

Answer 1

The molar mass of NO₂ is 46.0 g/mol

The molar mass of Pb (NO₃)₂ is 331.2 g/mol

First there is a need to find the number of moles of NO₂ via the stoichiometry of reaction:

2Pb(NO₃)₂ → 2PbO (s) + 4NO₂ (g) + 02 (g)

2 × 331.2 g = 4 × 46.0 g

16.87 g = x (mass of NO₂)

mass of NO₂ = 16.87 × 4 × 46 / 2 × 331.2

mass of NO₂ = 3104.08 / 662.4

mass of NO₂ = 4.686 g of NO₂

Now the number of moles are:

1 mole NO₂ = 46.0 g

x moles of NO₂ = 4.686 g

4.686 × 1 / 46.0 = 0.101 moles of NO₂

1 mole = 22.4 L (at STP)

0.101 moles of NO₂ = 0.101 × 22.4 / 1

= 2.26 L