Answer:
Step-by-step explanation:
a + 143 = 180 {Linear pair}
a = 180 - 143
a = 37
37 + 93 + b = 180 {Angle sum property of triangle}
130 + b = 180
b = 180 - 130
b = 40
c + b = 90
c + 40 = 90
c = 90 - 40
c = 50
d + 120 = 180 {Linear pair}
d = 180 - 120
d = 60
? = 60 + 40 {Exterior angle property of triangle}
? = 100
Hey there!
![\left[\begin{array}{ccc}\boxed{\boxed{ \frac{6}{4}}} \end{array}\right] = \left[\begin{array}{ccc}\boxed{\boxed{150}}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B%20%5Cfrac%7B6%7D%7B4%7D%7D%7D%20%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B150%7D%7D%5Cend%7Barray%7D%5Cright%5D%20)
All I did was to multiply each side by 100 which then go me this!
Hope this helps!
H=2ft
d=6 ft
r=d/2
r=6/2=3ft
V= π•r^2•h
V=3.14•3^2•2
V=3.14•9•2
V=56.52 ft3
V~56.5ft3
Answer: x = 0.75
Step-by-step explanation:
3x+x - 3 =0
4x - 3=0
4x = 3
x = 0.75
The altitude's slope must be perpendicular to that of the line.
The slope of segment BC is 2/5. The slope of the altitude must be perpendicular to 2/5. Since the negative reciprocal of 2/5 is -5/2, then the slope of the altitude is -5/2.
