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forsale [732]
3 years ago
12

The primary job of a(n) ______ on a receiver is to capture modified radio waves.

Physics
2 answers:
PilotLPTM [1.2K]3 years ago
8 0
The correct answer is antenna.
Mars2501 [29]3 years ago
7 0

Answer: The correct answer is an antenna.

Explanation:

In radio communication, radio receives radio waves which is an electromagnetic wave. It converts the information carried by them to usable form.

An antenna intercepts radio waves. It converts  them to tiny alternating current which are applied to receiver. Then, receiver extracts the desired information.

Therefore, the primary job of an antenna on a receiver is to capture modified radio waves

You might be interested in
The diagram below shows a periodic wave. Which two points on the wave are 180 degrees out of phase?
Ksju [112]

Answer:

A and C are 180 deg out of phase (opposite points on a 360 deg wave)

3 0
3 years ago
An astronaut, of total mass 86.0 kg including her suit, stands on a spherical satellite of mass 360 kg, both at rest relative a
Afina-wow [57]

Answer: 0.56 m/s

Explanation:

Hi, to answer this question we have to apply the formula of the conservation of momentum.

m1 v1 = m2 v2 (because the system is stationary at the beginning)

Where:

m1 = mass of the astronaut

v1= velocity of the astronaut

m2= mass of the satellite

v2= velocity of the satellite

Replacing with the values given and solving:

86 kg (2.35m/s) = 360 kg v2

202.1 kgm/s=360kg v2

202.1kgm/s /360kg =v2

v2 = 0.56 m/s

Feel free to ask for more if needed or if you did not understand something.

5 0
3 years ago
Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. F
Art [367]

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

4 0
3 years ago
1123123213213242141241
schepotkina [342]

Answer:

thanks for the points

Explanation:

8 0
3 years ago
4. How does density affect refraction of a lightwave?
Brums [2.3K]

optical density would increase the refraction angle going in to the material

there may be a relation between opt density and mass density ... kg/m^3

7 0
3 years ago
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