Answer:
A and C are 180 deg out of phase (opposite points on a 360 deg wave)
Answer: 0.56 m/s
Explanation:
Hi, to answer this question we have to apply the formula of the conservation of momentum.
m1 v1 = m2 v2 (because the system is stationary at the beginning)
Where:
m1 = mass of the astronaut
v1= velocity of the astronaut
m2= mass of the satellite
v2= velocity of the satellite
Replacing with the values given and solving:
86 kg (2.35m/s) = 360 kg v2
202.1 kgm/s=360kg v2
202.1kgm/s /360kg =v2
v2 = 0.56 m/s
Feel free to ask for more if needed or if you did not understand something.
Answer:
37.8 m
Explanation:
At point 0, the ball is at height y₀.
At point 1, the ball is at height 30 m.
At point 2, the ball is at height 0 m.
Given:
y₁ = 30 m
y₂ = 0 m
v₀ = 0 m/s
a = -10 m/s²
t₂ − t₁ = 1.5 s
Find: y₀
Use constant acceleration equation.
y = y₀ + v₀ t + ½ at²
Evaluate at point 1.
y₁ = y₀ + v₀ t₁ + ½ at₁²
30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²
30 = y₀ − 5t₁²
Evaluate at point 2.
y₂ = y₀ + v₀ t₂ + ½ at₂²
0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²
0 = y₀ − 5t₂²
y₀ = 5t₂²
Substitute:
y₀ = 5 (1.5 + t₁)²
y₀ = 5 (2.25 + 3t₁ + t₁²)
y₀ = 11.25 + 15t₁ + 5t₁²
30 = 11.25 + 15t₁ + 5t₁² − 5t₁²
30 = 11.25 + 15t₁
t₁ = 1.25
30 = y₀ − 5t₁²
30 = y₀ − 5(1.25)²
y₀ ≈ 37.8
optical density would increase the refraction angle going in to the material
there may be a relation between opt density and mass density ... kg/m^3
