Answer: 0.5 seconds or 2.625 seconds
Explanation:
At t = 0, The ball is 4 ft above the ground.
The height of the football varies with time in the following way:
s(t) = -16 t² + 50 t + 4
we need to find the time in which the height would of the football would be 25 ft:
⇒25 = -16 t² + 50 t + 4
we need to solve the quadratic equation:
⇒ 16 t² - 50 t + 21 = 0

⇒ t = 0.5 s or 2.625 s
Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.
Answer:
Given
mass (m) =2kg
velocity (v) =3m/s
momentum (p) =?
Form
p=mv
2kgx3m/s
p=6kg.m/s
the momentum of ball's =6kg.m/s
<span>Heat transfer between two substances is affected by specific heat and the "Temperature difference between them"
Hope this helps!</span>