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photoshop1234 [79]
3 years ago
7

In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.

Kepler-12b, has a diameter that is 1.7 times that of Jupiter (RJupiter = 6.99 × 107 m), but a mass that is only 0.43 that of Jupiter (MJupiter = 1.90 × 1027 kg ).
Physics
1 answer:
Leto [7]3 years ago
4 0

Answer:

g= 3.86 m/s^2

Explanation:

given : Kepler-12b, has a diameter that is 1.7 times that of Jupiter (R_Jupiter = 6.99 × 10^7 m), but a mass that is only 0.43 that of Jupiter (M_Jupiter = 1.90 × 10^27 kg ).

to calculate gravity we use the formula

g = GM/r^2

g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2

g = 3.859 ~ 3.86 m/s^2

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Calculate the aceleration of a vehicle if the initial velocity (Vi) is 20 m/s and acelerates to 40 m/s (V) in 3,8 s. (t).
tekilochka [14]

Hello!!

For calculate the aceleration of the vehicle let's applicate formula:

\boxed{V=V_i + a*t}

\textbf{Being:}

\sqrt{} V = Final velocity = 40 m/s

\sqrt{} Vi = Initial velocity = 20 m/s

\sqrt{} a = Aceleration = ?

\sqrt{} t = Time = 3,8 su

⇒ \text{Then let's \textbf{replace it according} we information:}

40 \  m / s = 20 \ m / s + a * 3,8 s

⇒ \text{We clear the "a"}

a = \dfrac{40 \ m /s - 20 \ m /     s }{3,8 \ s}

⇒ \text{Let's resolve it: }

a = 5,263         \                                              m /                                                       s

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4 0
3 years ago
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The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on
alekssr [168]

Answer:

The change in temperature is \Delta T  = 1795 K

Explanation:

From the question we  are told that

   The temperature coefficient is  \alpha  =  4 * 10^{-3 }\  k^{-1 }

The resistance of the filament is mathematically represented as

           R  =  R_o [1 + \alpha  \Delta T]

Where R_o is the initial resistance

Making the change in temperature the subject of the formula

     \Delta T = \frac{1}{\alpha } [\frac{R}{R_o} - 1 ]

Now from ohm law

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This implies that current varies inversely with current so

           \frac{R}{R_o} = \frac{I_o}{I}

Substituting this we have

       \Delta T  = \frac{1}{\alpha } [\frac{I_o}{I} - 1 ]

From the question we are told that

    I  = \frac{I_o}{8}

Substituting this we have

   \Delta T  = \frac{1}{\alpha } [\frac{I_o}{\frac{I_o}{8} } - 1 ]

=>     \Delta T  = \frac{1}{3.9 * 10^{-3}} (8 -1 )

        \Delta T  = 1795 K

6 0
4 years ago
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