Answer:
Efficiency = 52%
Explanation:
Given:
First stage
heat absorbed, Q₁ at temperature T₁ = 500 K
Heat released, Q₂ at temperature T₂ = 430 K
and the work done is W₁
Second stage
Heat released, Q₂ at temperature T₂ = 430 K
Heat released, Q₃ at temperature T₃ = 240 K
and the work done is W₂
Total work done, W = W₁ + W₂
Now,
The efficiency is given as:
or
Work done = change in heat
thus,
W₁ = Q₁ - Q₂
W₂ = Q₂ - Q₃
Thus,
or
or
also,
or
thus,
thus,
or
or
Efficiency = 52%
No. Any amount of gas always expands to completely fill
whatever container it's in.
So, as you take oxygen out of the tank, the pressure of what's
left in the tank certainly becomes less and less, but whatever is
left in the tank always expands and fills the whole tank.
(And then, eventually, when the pressure inside the tank drops
to equal the pressure outside it (atmospheric pressure), you could
cut off the whole top of the tank and nothing more would come out.)
SCUBA divers regularly talk about having a 'full tank', and 'half a tank',
and maybe a 'quarter tank'. But that refers to the amount of time that
the tank can still deliver air to them under water. It's not the amount
of volume inside the tank that's full or empty. The inside of the tank
is always full.
Think about it this way: ==> There's no way to take half of the air
out of a balloon, leaving it half empty and still inflated. Doesn't happen.
Hi there!
Acceleration = change in velocity / change in time = Δv/Δt
Thus:
a = (75 - 15)/4 = 60/4 = 15 mi/hr²
Answer:
W = 8.01 × 10^(-17) [J]
Explanation:
To solve this problem we need to know the electron is a subatomic particle with a negative elementary electrical charge (-1,602 × 10-19 C), The expression to calculate the work is given by:
W = q*V
where:
q = charge = 1,602 × 10^(-19) [C]
V = voltage = 500 [V]
W = work [J]
W = 1,602 × 10^(-19) * 500
W = 8.01 × 10^(-17) [J]
Answer:
Velocity
Explanation:
Velocity is a speed with a direction.
