3 years ago

Describe how you could have $0.87 with the least number of coins possible

2 answers:

5 0

3 quarters (75 cents) 1 dime (10 cents) 2 pennies (2 cents) 75+10+2=87 | 6 coins

Or, with half dollar coins:

1 half dollar coin (50 cents) 1 quarter (25 cents) 1 dime (10 cents) 2 pennies (2 cents) 50+25+10+2=87 | 5 coins

PolarNik [594]3 years ago

3 0

3 quarter, 1 dime and 2 pennies

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