1 μL = 10^-6 L by definition
So...
82 μL = 82x10^-6 L = 8.2x10^-5 L
Answer:
The answer to your question is empirical formula Al₃O₉S
Explanation:
Data
Al = 31.5 %
O = 56.1 %
S = 12.4 %
Process
1.- Look for the atomic masses of the elements
Al = 27 g
O = 16
S = 32
2.- Represent the percentages as grams
Al = 31.5 g
O = 56.1 g
S = 12.4 g
3.- Convert these masses to moles
27 g of Al ----------------- 1 mol
31.5 g ---------------------- x
x = 1.17 moles
16 g of O ---------------- 1 mol
56.1 g of O ------------- x
x = 3.5 mol
32 g of S --------------- 1 mol
12.4 g of S ------------- x
x = 0.39 moles
4.- Divide by the lowest number of moles
Al = 1.17 / 0.39 = 3
O = 3.5 / 0.39 = 8.9 ≈ 9
S = 0.39 / 0.39 = 1
5.- Write the empirical equation
Al₃O₉S
Answer:
True
Explanation:
Both work because an element would be pure and compounds can be split into elements. This will work unless the substance isnt chemcially pure, but in this case it is so the answer would be true.
The reaction will be spontaneous if Gibb free energy is negative, according the following relation:
G = H - T*S
where G is Gibbs free energy, T is change of enthalpy , T is temperature and S is change of entropy
In the case of ammonia:
G = -93000 - 356*(-198) = -93000 + 70488 = -22512 j/mol
As G < 0 then the reaction is spontaneous.
