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MissTica
3 years ago
12

In a car lot,4/12 of the cars are white and 3/12 of the cars are blue.What is the fraction of the cars in the lot are either whi

te or blue?
Mathematics
2 answers:
GalinKa [24]3 years ago
8 0
7/12 because 4/12 + 3/12 equals 7/12
Elan Coil [88]3 years ago
4 0
Well 3 twelfths and 4 twelfths equal 7 twelfths meaning 7 are either white or blue while the last 5 are unknown.
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Answer:

point-slope form:

y - 10 = -4(x - -2)

y - 10 = -4(x + 2)

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slope-intercept form:

y - 10 = -4x - 8

y = -4x - 8 + 10

y = -4x + 2

Step-by-step explanation:

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The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha
kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

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  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

\mu = 3500 \times 0.0004 = 1.4

The probability that 2 or fewer cars will be stolen is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466

P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452

P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

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The circumference of this circle is c=94.25ft
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