Explanation: Electronic configuration of Sodium is as follow,
Na = 11 = 1s², 2s², 2p⁶, 3s¹
As shown in electronic configuration, Sodium has 1 valence electrons in its valence shell. Therefore, to complete its noble gas configuration it donates one electron form Na⁺.
Na⁺ = 1s², 2s², 2p⁶
Electronic configuration of Fluorine is as follow,
F = 9 = 1s², 2s², 2p⁵
As shown in electronic configuration, fluorine has 7 valence electrons in its valence shell. Therefore, to complete its noble gas configuration it accepts one electron from Na to form F⁻.
F⁻ = 1s², 2s², 2p⁶
Henec, in order to form a neutral molecules, one Na⁺ combines with one F⁻ to form NaF.
Stearic acid formula is CH₃(CH₂)₁₆COOH The molecular mass of stearic acid is 284.48 g/mol The mass of stearic acid in 1 ml of solution is 0.1 g Therefore number of moles in 1 ml is - 0.1 g / 284.48 g/mol = 0.000352 mol Molarity is number of moles in 1 L of solution If 1 ml contains - 0.000352 mol Then 1 L solution contains - 0.000352 /1 x 1000 = 0.352 mol/L Therefore molarity is 0.352 M
Esterification is the process in which alkanol and alkanoic acids reacts in the presence of a catalyst and heat. The product is usually an ester(alkanoate) and water.
For the reaction between ethanoic acid and 1-butanol, the product is butylethanoate and water as shown below:
