1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VashaNatasha [74]
3 years ago
8

While leaning out a window that is 5.70 m above the ground, you drop a 0.600-kg basketball to a friend at ground level. Your fri

end catches the ball at a height of 2.00 m above the ground. Determine the following.
(a) the amount of work done by the force of gravity on the ball
(b) the gravitational potential energy of the ball-Earth system, relative to the ground when it is released
(c) the gravitational potential energy of the ball-Earth system, relative to the ground when it is caught
(d) the ratio of the change (PEf − PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity
Physics
1 answer:
Oliga [24]3 years ago
8 0

Answer:

a)21.756 J

b)33.516 J

c)11.52 J

d)-1

Explanation:

Net fall in height of ball= 5.70-2.0= 3.70 m

a)  work done by the force of gravity on the ball = Mg*h = 0.6×9.8×3.7 = 21.756 J

b) gravitational potential energy of the ball-earth system, relative to the ground when it is released = 0.6×9.8×5.70 = 33.516 J (ans)

c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught = 0.6×9.8×2 = 11.52 J

d) ratio of the change (PE_f − PE_0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity = (11.52 -33.51)/(21.756) ≅-1 (ans)

You might be interested in
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 2 sin2(t), y = 2 cos2(
Tanya [424]

The distance traveled by the particle at the given time interval is 0.28 m.

<h3>Position of the particle at time, t = 0</h3>

The position of the particle at the given time is calculated as follows;

x = 2 sin2(t)

y = 2 cos2(t)

x(0) = 2 sin2(0) = 0

y(0) = 2 cos2(0) = 2(1) = 2

<h3>Position of the particle at time, t = 4</h3>

x = 2 sin2(t)

y = 2 cos2(t)

x(4) = 2 sin2(4) = 0.28

y(4) = 2 cos2(4) = 2(1) = 1.98

<h3>Distance traveled by the particle at the given time interval</h3>

d = √[(x₄ - x₀)² + (y₄ - y₀)²]

d =  √[(0.28 - 0)² + (1.98 - 2)²]

d = 0.28 m

Thus, the distance traveled by the particle at the given time interval is 0.28 m.

Learn more about distance here: brainly.com/question/23848540

#SPJ1

7 0
2 years ago
Which equation describes the line containing the points (-2, 3) and (1, 2)​
snow_lady [41]

Answer:

y =  \frac{ - 1}{3}x +  \frac{7}{3}

Explanation:

\frac{y - 3}{2 - 3}  =  \frac{x + 2}{1 + 2}  \\  \ - y + 3 =  \frac{x + 2}{3}  \\  y =   \frac{ - 1}{3}x  +  \frac{7}{3}

8 0
3 years ago
If a 60-g object has a volume of 30 cm", what is its density?
alisha [4.7K]

Answer:

Density = Mass/volume. D= 60/30.Divide it and you'll get ur answer as 2

5 0
3 years ago
Five different forces act on an object. Is it possible for the net force on the object to be zero?
bazaltina [42]
No because there must be an even # if their is an even amount one of the forces isn’t being cancelled
4 0
3 years ago
During which phase of the moon do neap tides occur?
Fynjy0 [20]

Answer:

First Quarter and Third Quarter.

Explanation:

Tides are formed as a consequence of the differentiation of gravity due to the Moon across to the Earth sphere.

Since gravity variates with the distance:

F = G\frac{m1\cdot m2}{r^{2}} (1)

Where m1 and m2 are the masses of the two objects that are interacting and r is the distance between them.

For example, seeing the image below, point A is closer to the Moon than point b, and at the same time the center of mass of the Earth will feel more attracted to the Moon than point B. Therefore, that creates a tidal bulge in point A and point B.

When the Sun and the Moon are alight with respect to the Earth, then the Sun tidal force contributes to the tidal force of the Moon over the Earth. That makes the high tides even higher (spring tides).

               

However, when the Sun is not in the same line than the Moon (the Moon is at 90° with respect to the Sun), then the low tides are higher and the high tides are lower. That scenario is known as neap tides.

           

Therefore, that happens when the Moon is at First Quarter and Third Quarter.

4 0
3 years ago
Read 2 more answers
Other questions:
  • Calculate the volume of a 45 kg bucket knowing its density which is 2.7 kg/m3 (cubic meters)
    8·1 answer
  • An object starts at Xi = -4m with an initial velocity of 4m/s. It experiences an acceleration of -2 m/s^2 for 2 seconds, followe
    11·1 answer
  • An electric generator uses __________ to convert mechanical energy into electrical energy.
    14·1 answer
  • The chemical formula of glucose is C6H1206, so it is classified as a(n)
    13·1 answer
  • How does a cockcroft walton generator work?
    14·1 answer
  • A wire of length L and cross-sectional area A has resistance R.
    13·1 answer
  • A 120 g block attached to a spring with spring constant 3.0 N/m oscillates horizontally on a frictionless table. Its velocity is
    13·1 answer
  • A 190 g glider on a horizontal, frictionless air track is attached to a fixed ideal spring with force constant 160 N/m. At the i
    10·1 answer
  • A baseball player hits a ball with 400 n of force.how much does the ball exert on the bat
    14·1 answer
  • Compare the percent change in angular momentum of the system to the percent change in the rotational kinetic energy of the syste
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!