1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
taurus [48]
3 years ago
15

At depths of greater than 60 m, ice moves by plastic deformation. What causes this transition from brittle to ductile behavior?

Physics
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

Increase in the intensity of pressure allows very less deformation

Explanation:

For the water the variation of pressure at any depth is directly proportional to the depth of the water above that level.

Thus, at depth greater than 60 m the intensity of pressure on ice is very high and therefore very little deformation is possible.

Hence, the transition from brittle to ductile behavior is observed.

You might be interested in
John realized that his orchard has been invaded by certain harmful invasive plants. These plants are consuming all the soil nutr
Dovator [93]
John used smothering as the method to control the harmful invasive plants in his orchard. Smothering is an example of a manual method of control and it works best in a small population of invasive species. Smothering involves covering the invasive species with a barrier that is highly impenetrable for one growing season in order to prevent these species from thriving in the environment.
7 0
3 years ago
All electromagnetic waves
ANEK [815]
Electromagnetic Waves:

Radio waves, television waves, and microwaves.

3 0
3 years ago
1. Place these unknown pH test papers in order from most acidic to most alkaline.
Naddika [18.5K]

Answer: B

Explanation: look at the chart, easy

7 0
2 years ago
A proton moves perpendicular to a uniform magnetic field B at a speed of 2.30 107 m/s and experiences an acceleration of 1.70 10
anzhelika [568]

Answer:

Explanation:

Given the following :

Speed (V) = speed of 2.30×10^7 m/s

Acceleration (a) = 1.70×10^13 m/s^2

Using the right hand rule provided by  Lorentz law:

B = F / qvSinΘ

Where B = magnitude of the magnetic field

v = speed of the particle

Θ = 90° (perpendicular to the field)

q = charge of the particle

SinΘ = sin90°  = 1

Note F = ma

Therefore,

B = ma / qvSinΘ

Mass of proton = 1.67 × 10^-27

Charge = 1.6 × 10^-19 C

B = [(1.67 × 10^-27) × (1.70 × 10^13)] / (1.6 × 10^-19) × (2.30 × 10^7) × 1

B = 2.839 × 10^-14 / 3.68 × 10^-12

B = 0.7715 × 10^-2

B = 7.72 × 10^-3 T

2) Magnetic field will be in the negative y direction according to the right hand thumb rule.

Since Velocity is in the positive z- direction, acceleration in the positive x - direction, then magnetic field must be in the negative y-direction.

5 0
3 years ago
Find electric field at point p which is a distance l away from the both +q and -q
denis-greek [22]

Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

  • q is the charge
  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

8 0
3 years ago
Other questions:
  • If the power of an engine is known and the amount of time that the engine exerts this power is known, what can be calculated?
    11·1 answer
  • An 12 N force is applied to a 1 kg object. What is the magnitude of the objects acceleration?
    11·1 answer
  • Which fundamental force is responsible for some kinds of radioactivity
    11·1 answer
  • two equal and unlike parallel forces of magnitude 34N act on a rigid body,such that the moment of couple is 8.50 Nm. calculate t
    12·1 answer
  • Which statements does the Second Law of Thermodynamics support?
    13·1 answer
  • Petroleum is a nonrenewable resource. true or false
    13·1 answer
  • A long, hollow wire with inner radius a and outer radius b carries a uniform current density J. What is the magnetic field as a
    6·1 answer
  • A stretched rubber band is an example of which type potential energy
    9·2 answers
  • Please help, i’ll give brainliest!!
    12·1 answer
  • I stand 0.72 meters in front of a mirror and look at the person on the other side who looks like me. That person is actually you
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!