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4 years ago

At depths of greater than 60 m, ice moves by plastic deformation. What causes this transition from brittle to ductile behavior?

Physics

1 answer:

mafiozo [28]4 years ago

3 0

Answer:

Increase in the intensity of pressure allows very less deformation

Explanation:

For the water the variation of pressure at any depth is directly proportional to the depth of the water above that level.

Thus, at depth greater than 60 m the intensity of pressure on ice is very high and therefore very little deformation is possible.

Hence, the transition from brittle to ductile behavior is observed.

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After hitting the spring, the block is bounced back up the ramp. The maximum compression of the spring is Δx=0.03m, and the spri

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Answer:

v = 1.28 m/s

Explanation:

Given that,

Maximum compression of the spring, $\Delta x=0.03\ m$

Spring constant, k = 800 N/m

Mass of the block, m = 0.2 kg

To find,

The velocity of the block when it first reaches a height of 0.1 m above the ground on the ramp.

Solution,

When the block is bounced back up the ramp, the total energy of the system remains conserved. Let v is the velocity of the block such that,

Initial energy = Final energy

$\dfrac{1}{2}kx^2=mgh+\dfrac{1}{2}mv^2$

Substituting all the values in above equation,

$\dfrac{1}{2}\times 800\times 0.03^2=0.2\times 9.8\times 0.1+\dfrac{1}{2}\times 0.2\times v^2$

v = 1.28 m/s

Therefore the velocity of block when it first reaches a height of 0.1 m above the ground on the ramp is 1.28 m/s.

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Answer:

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