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taurus [48]
4 years ago
15

At depths of greater than 60 m, ice moves by plastic deformation. What causes this transition from brittle to ductile behavior?

Physics
1 answer:
mafiozo [28]4 years ago
3 0

Answer:

Increase in the intensity of pressure allows very less deformation

Explanation:

For the water the variation of pressure at any depth is directly proportional to the depth of the water above that level.

Thus, at depth greater than 60 m the intensity of pressure on ice is very high and therefore very little deformation is possible.

Hence, the transition from brittle to ductile behavior is observed.

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Find the acceleration of the system and the tension in the ropes for the system shown. The table mass is 30 kg and the hanging m
marusya05 [52]

The system's tension is 616 N and acceleration is 5.6 m / s^{2}

<u>Explanation:</u>

From newton’s second law of motion which state that net force acting on a body is product of mass of a body and acceleration of a body which is given as,

             F_{n e t}=m_{t o t} \times a

Where,

F_{n e t} is net force acting on body

m_{\mathrm{tot}} is mass of body

a is acceleration of body

Given values  

Table mass (m) = 30 kg

Hanging mass (m) = 40 kg

                a=\frac{F_{n e t}}{m_{\mathrm{tot}}}=\frac{m \times g}{m_{\mathrm{tot}}}

Put the value for m = hanging mass = 40 kg and g=9.8 \mathrm{m} / \mathrm{s}^{2}, we get

                  a=\frac{40 \times 9.8}{30+40}=\frac{392}{70}=5.6 \mathrm{m} / \mathrm{s}^{2}

The tension in the ropes,  T=(m \times g)+(m \times a)

Here, m as hanging mass

T = tension, N or  k g m / s^{2}

m = mass, kg  

g = gravitational force, 9.8 \mathrm{m} / \mathrm{s}^{2}

a = acceleration, m / s^{2}

          T = (40 \times 9.8)+(40 \times 5.6) = 392+224 = 616 N

3 0
3 years ago
Can someone help me with these physics questions?
wariber [46]

hi! Glad to help =)

1. would be c

2 would be d

3 would be A

6 0
3 years ago
A fan connected to a 120-volt electrical system by an extension cord was worn through and exposed the bare, energized conductor,
kari74 [83]

Answer: the ladder

Explanation: since the energized conductor is already in contact with the ladder there by making electric current to flow. The base of the ladder is on the ground there by making the circuit to be complete and causing electrocution.

8 0
3 years ago
Read 2 more answers
SOMEBODY PLEASE HELP!!! Indicate the reasons why the centripetal acceleration (and centripetal force) always point to the center
maxonik [38]
Well we know the correct answer cannot be "a" bcause velocity is tangent to the circlular path of an object experienting centripical motion. Velocity DOES NOT point inward in centripical motion.

we know the correct answer cannot be "b" because "t" stands for "time" which cannot point in any direction. so, time cannot point toward the center of a circle and therefore this answer must be incorrect.

I would choose answer choice "c" because both force and centripical acceleration point toward the center of the circle.

I do not think answer choice "d" can be correct because the velocity of the mass moves tangent to the circle. velocity = (change in position) / time. Therefore, by definition the mass is moving in the direction of the velocity which does not point to the center of the circle.

does this make sense? any questions?

3 0
3 years ago
Convert the following quantities <br><img src="https://tex.z-dn.net/?f=25m%20%7B%7D%5E%7B2%7D%20%20%5C%3A%20into%20%5C%3A%20cm%2
Bad White [126]

Answer:

\rm 250000 \; cm^2

Explanation:

Refer to the attachment.

8 0
3 years ago
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