All categories

4 years ago

Which of the following elements has two valence electrons? Na MG AL S

Chemistry

2 answers:

jeka57 [31]4 years ago

7 0

Hello!

From the list you gave, Mg (Magnesium) is the element that has two valence electrons

Why?

The valence electrons are the electrons that are found in the outer shell of the atom. That is, the shell with the highest "n" number.

From the list, the electron configuration of the atoms is:

Na: [Ne] 3s¹. 1 Valence Electron.
Mg: [Ne] 3s². 2 Valence Electrons.
Al: [Ne] 3s² 3p¹. 3 Valence Electrons.
S: [Ne] 3s² 3p⁴. 6 Valence Electrons.

The atom that has Two Valence Electrons from the list is Magnesium (Mg)

Have a nice day!

goldfiish [28.3K]4 years ago

4 0

Mg
......
Electron configuration:
²⁴₁₂Mg: 1s² 2s² 2p⁶ 3s²

>>> 3s² - valence shell with 2 valence electrons

You might be interested in

How many electrons does a Bromine (Br) atom have?

Usimov [2.4K]

35 yooooooooo...........

8 0

3 years ago

Which of the following is a consequence of humans using fossil fuels?

julia-pushkina [17]

I think it’s A, because all of these are related to fossil fuel somehow.

4 0

3 years ago

How many square centimeters are in an area of 8.10inch2 ?

In-s [12.5K]

$8.10in^2=52.25796cm^2$

$1 in^2=6.4516cm^2$

$8.10in^2*6.4516cm^2/1 in^2$

$8.10in^2*6.4516cm^2= 52.25796 cm^2$

5 0

3 years ago

If a drop of red ink is placed in one end of a shallow pan filled with water, and a drop of blue ink is placed in the other end,

steposvetlana [31]

The red and blue will spread from the drops which will mix causing purple at the meeting and red pat that then over time it will spread to a murky purple

3 0

3 years ago

A sample of pure lithium carbonate contains 18.8% lithium by mass. What is the % lithium by mass in a sample of pure lithium car

VashaNatasha [74]

Answer:

There is 18.8% lithium by mass in second sample

Explanation:

Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-

Let's assume weight of first sample is x g

So, 100 g of sample contains 18.8 g of lithium

Hence, x g of sample contains $(\frac{18.8}{100}\times x)$ g of lithium

Now, the second sample has weight equal to 2x g

So, 2x g of sample contains $(\frac{18.8}{100}\times 2x)$ g of lithium

So, % lithium by mass in second sample = $(\frac{\frac{18.8}{100}\times 2x}{2x})\times 100$ % = 18.8%

4 0

4 years ago