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Sedaia [141]
3 years ago
13

I don’t understand how to find these please help

Chemistry
1 answer:
ddd [48]3 years ago
5 0

Answer:

8 shared electrons

Explanation:

When you are looking for the number of shared electrons via the equation:

S = N-A

Where:

S = means the shared electrons

N = Needed electrons

A = available electrons

"Needed electrons" means how many electrons does it need to have a noble gas configuration, in this case, to complete the octet rule.

"Available electrons" means how many valence electrons is actually available considering the compound or the elements involved in the compound.

To get the needed electrons, treat the elements involved separately.  We have a silicon (Si) atom and 4 chlorine (chlorine) atoms in this compound. Let's list it down first:

              Number of atoms

Si                      1

Cl                     4

Next step is to determine how many electrons should it have in its outer shell to achieve the octet rule. Both of them in this case would be 8. Multiply that by the number of atoms and add up the needed electrons to determine how many you will need for this particular compound.

        <u>      Number of atoms             Electrons to achieve Octet       Needed</u>

Si                      1                      x                         8                           =       8

Cl                     4                      x                         8                           = <u>     32</u>

                                                                     TOTAL:                              40

This is now our N. N = 40 electrons

Next step is to determine how many we actually have. Your clue in determining how many valence electrons the atom has is the group. Silicon is in Group 4A, this means it has 4 valence electrons. Chlorine is in Group7A, so ths means it has 7 valence electrons.

So first we write the number of atoms again, then in the next column, you write down the actual number of valence electrons and multiply them. Sum it up to see how many electrons available  in this particular compound.

        <u>      Number of atoms             Valence electrons                 Available</u>

Si                      1                      x                         4                           =      4

Cl                     4                      x                         7                          = <u>     28</u>

                                                                     TOTAL:                              32

This is now our A. A = 32 electrons

Now we apply this:

S = N - A

N = 40 electrons

A =  32 electrons

S = 40 - 32 = 8

Number of shared electrons is 8

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givi [52]

Answer:

C.  Butanal , is the aldehyde

Explanation:

A . It is carboxylic acid : ---COOH group

B. It is Ester : ----COOR group , Here R = CH3

C. It is Aldehyde : -----CHO group

D. It is ketone : ----C=O group

See image :

8 0
3 years ago
How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
Serena is making an experiment. for that, she needs 20 grams of a 52% solution of salt. she has two large bottles of salt water:
maksim [4K]
This is a simple algebraic problem, specifically for the mixture type of problem. Let x be the mass of 40% solution and y be the mass of 70% solution. The first equation would then be:

x + y = 20 --> eqn 1

The second equation would be the mass balance shown below:

(x)(0.40) + y(0.70) = 20(0.52) --> eqn 2

Rearranging eqn 1,
x = 20 - y
Substitute this to eqn 2:

(20 - y)(0.40) + y(0.70) = 20(0.52)
Solve for y,
y = 8 grams
 
Finally, solve for x.
x = 20 - 8 = 12 grams

<em>Therefore, Serena needs 12 grams of the 40% solution and 8 grams of the 70% solution.</em>
5 0
3 years ago
How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles?
yan [13]

Answer: There are 1.08 \times 10^{-14} moles N_{2}O_{4} present in 6.49 \times 10^9 particles.

Explanation:

According to the mole concept, 1 mole of a substance contains 6.022 \times 10^{23} particles.

Hence, number of moles present in 6.49 \times 10^9 particles are calculated as follows.

No. of moles = \frac{6.49 \times 10^9}{6.022 \times 10^{23}} mol

                      = 1.08 \times 10^{-14} mol

Thus, there are 1.08 \times 10^{-14} moles N_{2}O_{4} present in 6.49 \times 10^9 particles.

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C. soil. If this isn’t C it’s definitely B.
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