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Vladimir79 [104]
3 years ago
15

Part A Which acid in each of the following pairs has the stronger conjugate base? Match the words in the left column to the appr

opriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. ResetHelp Of the acids HCl or HF, the one with the stronger conjugate base is Of the acids H C l or H F, the one with the stronger conjugate base is blank.. Of the acids H2S or HNO2 , the one with the stronger conjugate base is Of the acids H 2 S or H N O 2 , the one with the stronger conjugate base is blank.. Of the acids H2CO3 or HClO4 , the one with the stronger conjugate base is Of the acids H 2 C O 3 or H C l O 4 , the one with the stronger conjugate base is blank.. Of the acids HF or NH4+, the one with the stronger conjugate base is Of the acids H F or N H 4 +, the one with the stronger conjugate base is blank..
Chemistry
1 answer:
vichka [17]3 years ago
6 0

Answer:

HF

H₂S

H₂CO₃

NH₄⁺

Explanation:

<em>Which acid in each of the following pairs has the stronger conjugate base?</em>

According to Bronsted-Lowry acid-base theory, <em>the weaker an acid, the stronger its conjugate acid</em>. Especially for weak acids, pKa gives information about the strength of such acid. <em>The higher the pKa, the weaker the acid.</em>

<em />

  • Of the acids HCl or HF, the one with the stronger conjugate base is HF because it is a weak acid.
  • Of the acids H₂S or HNO₂, the one with the stronger conjugate base is    H₂S  because it is a weaker acid. pKa (H₂S) = 7.04 > pKa (HNO₂) = 3.39
  • Of the acids H₂CO₃ or HClO₄, the one with the stronger conjugate base is H₂CO₃ because it is a weak acid.
  • Of the acids HF or NH₄⁺, the one with the stronger conjugate base is NH₄⁺ because it is a weaker acid. pKa (HF) = 3.17 < pKa (NH₄⁺) = 9.25
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Explanation:

In order to determine the kinetics of reaction let us consider the given data

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As with time one half of A remains and after equal time one fourth of A remains it means again the order of reaction is first with respect to A also.

There is no effect on the half life if we are decreasing the initial concentration of A also.

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cestrela7 [59]

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Determine the percent water in MgSO4*7H20?
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Answer:

\% H_2O=51.2\%

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol

Thus, the percent water is:

\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\

So we plug in to obtain:

\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%

Best regards!

5 0
3 years ago
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