Question

Q4. A particle starting from rest, travels with a = 5 m/s2. What is the distance traveled in 10 sec?

Answer 1

Answer:

250 m

Explanation:

Given :

Initial velocity, u = 0

Acceleration, a = 5 m/s2

Time elapsed is t = 10 seconds

The distance traveled in 10 seconds by the particle when accelerating at 5 m/s2 is given by,

$x = ut+\frac{1}{2}at^2$

Putting the values,

$x = 0\times 10+\frac{1}{2}(5)(10)^2$

$x =\frac{1}{2}(5)(100)$

x = 250 m

The particle moved 250 m in 10 seconds