Question

A 100 kg man is one fourth of the way up a 4.0 m ladder that is resting against a smooth, frictionless wall. The ladder has mass 25 kg and makes an angle of 56 degrees with the ground. What is the magnitude of the force of the wall on the ladder at the point of contact, if this force acts perpendicular to the wall and points away from the wall

Answer 1

Answer:

$N_f=248N$

Explanation:

From the question we are told that:

Mass $m=100kg$

Ladder Length $l=4.0m$

Mass of Ladder $m_l=25kg$

Angle $\theta=56 \textdegree$

Generally the equation for Co planar forces is mathematically given by

$mgcos \theta *2+Mgcos\theta*1 -N_fsin \theta*4=0$

Therefore

$25*9.81cos 56 *2+100*9.81cos56*1 -N_fsin 56*4=0$

$N_f=248N$