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Illusion [34]
3 years ago
10

Which one is greater 1/6 or 1/12​

Mathematics
2 answers:
Elza [17]3 years ago
7 0
1/6 is great because 2/12=1/6
Ede4ka [16]3 years ago
4 0

Answer:

1/6

Step-by-step explanation:

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Express your answer as a decimal.<br><br> 3÷2=
Darina [25.2K]

Answer:

1.5

Step-by-step explanation: please brainliest!

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3 years ago
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D= 7/2 cm
kvv77 [185]

Answer:

1) B

2) C

3) B

Step-by-step explanation:

Radius = D/2 = 7/2 × 2 = 7/4

Circumference = pi × D

= 7/2 pi

7/2 × 3.14 = 10.99

Approximately 11

3 0
4 years ago
V = u + at <br> u = 2 and a= -5 and t= 1/2<br> work out the value of v
Darina [25.2K]

Step-by-step explanation:

v=u+at

v=2+(-5)<u>1</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2

v=2-2.5

v=-0.5m/s²

hope it helps.

8 0
3 years ago
Read 2 more answers
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
. If n(A)=2 n(B)=3 n(AՈB) =24, what is the value of n(AUB)?​
____ [38]

Step-by-step explanation:

The answer is is the picture..

8 0
3 years ago
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