I need help with my homework

Simply the given expression. Type your answer in the blank. -10k+15+17k

dimaraw [331]

Simplify. Combine like terms

17k - 10k + 15

(17k - 10k) + 15

17k - 10k = 7k

7k + 15 is your answer

hope this helps

4 0

4 years ago

I need help please!!

Jobisdone [24]

A
B
C
E
F
G
(It’s basically just a game of making pairs)

4 0

3 years ago

Write the standard equation of a circle with center (2, −5) and radius 16.

astra-53 [7]

The standard equation of circle when center is (h,k) and radius is 'r'

$\left ( x - h \right )^{2} + \left ( y - k \right )^{2} = r^{2}$

h = 2 and k = - 5, radius = 16

So equation of the circle is given by

$\left ( x - 2 \right )^{2} + \left ( y - (-5) \right )^{2} = 16^{2}$

$\left ( x - 2 \right )^{2} + \left ( y + 5) \right )^{2} = 256$

7 0

4 years ago

Read 2 more answers

Find the slope-intercept form of an equation for the line that passes through (–1, 2) and is parallel to y = 2x – 3.

sukhopar [10]

Answer:

Option d is the correct answer

Step-by-step explanation:

The slope-intercept form of an equation for a line passing through given points can be represented as

y = mx + c

Where

Slope, m = (change in value of y on the vertical axis) / (change in value of x on the horizontal axis)

c = y-intercept

We want to find the slope-intercept form of an equation for the line that passes through (–1, 2) and is parallel to y = 2x – 3

For two lines to be parallel to each other, the slopes must be equal.

For y = 2x – 3

Slope,m = 2 (comparing with the slope intercept form stated above).

This means that the slope of the line

that passes through (–1, 2) is also 2

To find the y-intercept, c of this equation,

2 = 2 × - 1 + c

2 = -2 + c

c = 2+2 = 4

The equation is

y = 2x + 4

8 0

3 years ago

Dullco Manufacturing claims that its alkaline batteries last at least 40 hours on average in a certain type of portable CD playe

Gennadij [26K]

Answer:

$p_v =P(t_{17}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

The best option for this case would be:

We would switch to α = .01 for a more powerful test.

Step-by-step explanation:

Previous concepts and data given

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=37.8$ represent the sample mean

$s=5.4$ represent the sample standard deviation

n=18 represent the sample selected

$\alpha=0.05$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 40, the system of hypothesis would be:

Null hypothesis: $\mu \geq 40$

Alternative hypothesis: $\mu < 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{37.8-40}{\frac{5.4}{\sqrt{18}}}=-1.728$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

Since is a left tailed test the p value would be:

$p_v =P(t_{17}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

The best option for this case would be:

We would switch to α = .01 for a more powerful test.

Since the p values is just a little higher than th significance level 0.051>0.05 but the values are two close. If we change the value of the significance by 0.01, we have that 0.051>0.01 and it's a more powerful test.

4 0

3 years ago