Is chunky peanut butter homogeneous or heterogeneous

If the speed of a sound wave increases what other property of the wave must also increase when all other wave properties are hel

kati45 [8]

<h2>Frequency</h2>

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

Wave speed is the speed at which a wave travels.

Let the wave speed be $v$

Let the wave frequency be $f$

Let the wave length be $l$

The wave speed,frequency and wave length are related by the equation $v=f\times l$ .

When $v$ increases, $f$ increases on the other side to maintain equality when no other property is changing.

8 0

4 years ago

The dissociation of a/an ________ releases hydrogen ions and increases the concentration of hydrogen ions in a solution.

Crank

Acid...hope it helps

5 0

3 years ago

Does a large or small body cool faster?

Nataly [62]

Answer:

SO… The larger wire looses heat energy faster, however the smaller wire decreases temperature faster. ... Their surface area is much larger in proportion to their body mass and they lose heat through their skin when it is cold and they gain heat through their skin when it is hot much faster than an adult does.

Explanation:

8 0

3 years ago

Consider the following reaction between mercury(II) chloride and oxalate ion:

siniylev [52]

Answer : The reaction rate will be, $1.9\times 10^{-4}M/s$

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2HgCl_2(aq)+C_2O_2^{4-}(aq)\rightarrow 2Cl^-(aq)+2CO_2(g)+HgCl_2(s)$

Rate law expression for the reaction:

$\text{Rate}=k[HgCl_2]^a[C_2O_2^{4-}]^b$

where,

a = order with respect to $HgCl_2$

b = order with respect to $C_2O_2^{4-}$

Expression for rate law for first observation:

$3.2\times 10^{-5}=k(0.164)^a(0.15)^b$ ....(1)

Expression for rate law for second observation:

$2.9\times 10^{-4}=k(0.164)^a(0.45)^b$ ....(2)

Expression for rate law for third observation:

$1.4\times 10^{-4}=k(0.082)^a(0.45)^b$ ....(3)

Expression for rate law for fourth observation:

$4.8\times 10^{-5}=k(0.246)^a(0.15)^b$ ....(4)

Dividing 1 from 2, we get:

$\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{k(0.164)^a(0.45)^b}{k(0.164)^a(0.15)^b}\\\\9=3^b\\(3)^2=3^b\\b=2$

Dividing 3 from 2, we get:

$\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{k(0.164)^a(0.45)^b}{k(0.082)^a(0.45)^b}\\\\2=2^a\\a=1$

Thus, the rate law becomes:

$\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2$

Now, calculating the value of 'k' by using any expression.

Putting values in above rate law, we get:

$3.2\times 10^{-5}=k(0.164)^1(0.15)^2$

$k=8.7\times 10^{-3}M^{-2}s^{-1}$

Now we have to determine the reaction rate when the concentration of $HgCl_2$ is 0.135 M and that of $C_2O_2^{-4}$ is 0.40 M.

$\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2$

$\text{Rate}=(8.7\times 10^{-3})\times (0.135)^1\times (0.40)^2$

$\text{Rate}=1.9\times 10^{-4}M/s$

Therefore, the reaction rate will be, $1.9\times 10^{-4}M/s$

6 0

3 years ago

Hey I need help with this element, compound, and mixtures worksheet

Alika [10]

We should describe a little bit the legend.

A - Element - we should have circles with same color and not bonded together (argon gas).

B - Compound - here we may have circles with same or different color bonded together (water or oxygen which is a diatomic molecule).

C - Mixture of elements - circles with different colors not not bonded together (mixture of noble gases).

D - Mixture of compounds - circles with same or different color bonded together but we should see two or more types of connectivity between circles (mixture of water and ethanol).

E - Mixture of elements and compounds - circles with same or different color bonded together mixed with circles with same color and not bonded together (a mixture between oxygen which is a diatomic molecule and noble gas like argon).

Now we may answer the question:

1) B

2) C

3) D

4) D

5) A

6) B

7) B

8) E

9) E

10) D

11) B

12) D

13) D

14) D

15) D

7 0

3 years ago