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lora16 [44]
3 years ago
6

If you were trying to describe the difference between power and work you could say:

Physics
2 answers:
avanturin [10]3 years ago
6 0
Power is the energy transferred or "WORK DONE" in one second
nordsb [41]3 years ago
5 0

Answer:

Explanation:

Work done is defined as the product of force in the direction of displacement and the displacement.

Work = force in the direction of displacement x displacement

It is a scalar quantity and its SI uni is Joule.

Power is defined as the rate of doing work.

Power = Work / time

It is also a scalar quantity and its SI unit is Watt.

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30x30=900

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The current in resistor Y is..?
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(A)

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Read 2 more answers
A mass of 1000 kg drops from a height of 10 m on a platform of negligible mass. It is desired to design a spring and dashpot on
Juliette [100K]

Answer:

k = 5\times 10^{4}\ N/m

b = 0.707\times 10^{3}

t = 7.1\times 10^{- 5}\ s

Solution:

As per the question:

Mass of the block, m = 1000 kg

Height, h = 10 m

Equilibrium position, x = 0.2 m

Now,

The velocity when the mass falls from a height of 10 m is given by the third eqn of motion:

v^{2} = u^{2} + 2gh

where

u = initial velocity = 0

g = 10m/s^{2}

Thus

v = \sqrt{2\times 10\times 10} = 10\sqrt{2}\ m/s

Force on the mass is given by:

F = mg = 1000\times 10 = 10000 N = 10\ kN

Also, we know that the spring force is given by:

F = - kx

Thus

k = \frac{F}{x} = \frac{10000}{0.2} = 5\times 10^{4}\ N/m

Now, to find the damping constant b, we know that:

F = - bv

b = \frac{F}{v} = \frac{10000}{10\sqrt{2}} = 0.707\times 10^{3}

Now,

Time required for the platform to get settled to 1 mm or 0.001 m is given by:

t = \frac{0.001}{v} = \frac{0.001}{10\sqrt{2}} = 7.1\times 10^{- 5}\ s

4 0
3 years ago
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