Explanation:
Momentum before = momentum after
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
(65 kg) (0 m/s) + m (0 m/s) = (65 kg) (-3.5 m/s) + m (4 m/s)
m ≈ 57 kg
Answer:
The value is 
Explanation:
From the question we are told that
The speed of in a vacuum is 
The speed of light in the material is 
Generally the reflection of the material is mathematically represented as
=> 
=>
If three atoms of helium fuse to form carbon than 0.009 u of mass is converted into energy
Given: m(He) = 4.003 u
and m(C) = 12.000 u
Mass of 3 alpha particles =3×4.003 u
=12.009 u.
Mass of 1 carbon atom=12.000 u
Mass Defect =△m=12.009−12.000=0.009 u
Energy released =0.009×931.5=8.3835 MeV.
So, 0.009 u of mass is converted into 8.38 Mev energy.
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For an object that travels at a fixed speed along a circular path, the acceleration of the object is LARGER IN MAGNITUDE THE SMALLER THE RADIUS OF CIRCLE.
