We need a system to use those air vibrations to push against the surface of the inner ear fluid.
Answer:
Explanation:
distance of fan A = 18.3 m
distance of fan B = 127 m
speed of sound (s) = 343 m/s
What is the time difference between hearing the sound at the two locations?
time (T) = distance / speed
- time for sound to reach fan A = 18.3 / 343 = 0.053 s
- time it takes for sound to reach fan B = 127 / 343 = 0.370 s
- time difference = 0.370 - 0.053 = 0.317 s
Answer:
A) P1=2 [bar] , W=-12 [kJ]
B) P1=0.8 [bar] , W=-7.3303 [kJ]
C) P1=0.6077 [bar] , W=-6.4091 [kJ]
Explanation:
First, from the problem we know the following information:
V1=0.1 m^3
V2=0.04 m^3
P2=2 bar =200 kPa
The relation PV^n=constant means PV^n is a constant through all the process, so we can derive the initial pressure as:
a) To the case a) the constant n is equal to 0, we can calculate the initial pressure substituting n=0 in the previous expression, so:
The expression to calculate the work is:
If n=0:
Then:
The work is:
b) To the case b) the constant n is equal to 1, we can calculate the initial pressure substituting n=1 in the initial expression, so:
If n=1 then:
To calculate the work:
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Substituting:
c) To the case c) the constant n is equal to 1.3, we can calculate the initial pressure substituting n=1.3 in the initial expression, so:
First:
The work:
Substituting:
W=-6.4091 kJ
Kinetic energy is energy in motion, and it is a type of energy.
Answer:
a) ΔФ = 5.54 rad
, b) f = 140 Hz
Explanation:
a) This is a sound interference exercise, which is described by
Δr /λ = ΔФ / 2π
ΔФ = Δr 2π /λ
Let's find the path difference
Δr = r₂ -r₁
r₁ = 4m
r₂ = √ (x² + y²) = √(3² + 4²) = 5 m
Δr = 1 m
To find the wavelength we use the relation of the speed of sound
v = λ f
λ = v / f
λ = 340/300
λ = 1,133 m
We substitute
ΔФ = 2π 1 /1.133
ΔФ = 5.54 rad
b) to have a minimum intensity the phase difference must be π radians
λ = Δr 2π /Ф
λ = 1 2π /π
λ = 2m
We look for the frequency
v = λ f
f = v /λ
f = 340/2
f = 140 Hz