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3 years ago

If i click on a mouse does that show energy transfer?

Physics

2 answers:

Radda [10]3 years ago

8 0

Answer:

Yes

Explanation:

You are using energy to click the mouse, and the energy moves from your fingers to the mouse clicker.

dusya [7]3 years ago

4 0

Answer:

yes

Explanation:

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I NEED THE ANSWER ASAP I GIVE THANKS + 5 STARS

Kobotan [32]

Work or energy spent=force times distance=25N*4m=100Nm
power=energy or work divided by time=100Nm/5s=20Nm/s

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4 years ago

What force is a contact force?

kondaur [170]

Answer:

Explanation:

Contact force A contact force is any force that requires contact to occur. ... Contact forces are often decomposed into orthogonal components, one perpendicular to the surface (s) in contact called the normal force, and one parallel to the surface (s) in contact, called the friction force. In the Standard Model of modern physics, the four fundamental forces of nature are known to be non-contact forces.

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3 years ago

The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting

faltersainse [42]

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The equation for gravitational potential energy is GPE = mgh.

GPE = 1200(1.6)(350) = 672000 J

Hope this answers the question. Have a nice day.

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3 years ago

Read 2 more answers

Toon Train is traveling at the speed of 10 m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is

Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

initial velocity of the train, u = 10 m/s

change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

$a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2$

Therefore, the rate of acceleration of the train is 4 m/s²

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3 years ago

A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is

mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate = 150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

$h= \frac{1}{2}at^2$

$h= \frac{1}{2}4.71\times4.96^2$

h= 58.012 m

h≅ 58 m

4 0

3 years ago