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UNO [17]
3 years ago
13

On a velocity vs. time graph what does a straight line with negative tell you

Physics
2 answers:
8_murik_8 [283]3 years ago
4 0

-- If a velocity/time graph is a straight line, that tells us that the acceleration is constant.

-- If the line has negative <u><em>slope</em></u>, then we know that the acceleration is negative.

. . . As long as the line is above the x-axis, the object is moving forward but slowing down.  

. . . When the line drops below the x-axis, the object is moving backward and speeding up.

(If you meant that the line has negative-something-else, then I don't know what to tell you about that part.)

KonstantinChe [14]3 years ago
3 0
Velocity was slowing, it was going down
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Two particles are moving along the x axis. Particle 1 has a mass m₁ and a velocity v₁ = +4.7 m/s. Particle 2 has a mass m₂ and a
nirvana33 [79]

Answer:

m₁ / m₂ = 1.3

Explanation:

We can work this problem with the moment, the system is formed by the two particles

The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero

    p₀o = m₁ v₁ + m₂ v₂

    pf = 0

    m₁ v₁ + m₂ v₂ = 0

    m₁ / m₂ = -v₂ / v₁

    m₁ / m₂=  - (-6.2) / 4.7

     m₁ / m₂ = 1.3

Another way to solve this exercise is to use the mass center relationship

    Xcm = 1/M    (m₁ x₁ + m₂ x₂)

We derive from time

   Vcm = 1/M   (m₁ v₁ + m₂v₂)

As they say the velocity of the center of zero masses

    0 = 1/M   (m₁ v₁ + m₂v₂)

   m₁ v₁ + m₂v₂ = 0

    m₁ / m₂ = -v₂ / v₁

   m₁ / m₂ = 1.3

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3 0
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Hope this helps.

Please mark as brainliest if this helps.

5 0
4 years ago
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