Answer:
Acceleration, 
Explanation:
Given that,
Height from a ball falls the ground, h = 17.3 m
It is in contact with the ground for 24.0 ms before stopping.
We need to find the average acceleration the ball during the time it is in contact with the ground.
Firstly, find the velocity when it reached the ground. So,
u = initial velocity=0 m/s
a = acceleration=g
It is in negative direction, u = -18.41 m/s
Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.
So, the average acceleration of the ball during the time it is in contact is .
Answer:
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The answer for the following question is explained below.
- <u><em>Therefore the work done is 130 kilo Joules.</em></u>
Explanation:
Work:
A force causing the movement or displacement of an object.
Given:
mass of the person (m) = 65 kg
height of the cliff (h) = 2000 m
To calculate:
work done (W)
We know;
According to the formula:
<u>W = m × g × h</u>
Where;
m represents mass of the person
g represents the acceleration due to gravity
where the value of g is;
<u> g = 10 m/ s²</u>
h represents the height of the cliff
From the above formula;
W = 65 × 10 × 2000
W = 130,000 J
W = 130 Kilo Joules
<u><em>Therefore the work done is 130 kilo Joules.</em></u>
Answer:
false
Explanation:
Because the sun has ultraviolet rays
Answer:
y = 1.06 x + 0.14
r² = 0.95
Explanation:
a) To make this graph, a spreadsheet-type calculation program is used, see attached.
On the y axis are the measured values
On the x-axis, the values checked in the experiment are placed.
From the graph we see that a linear graph and that one of the values has a strong deviation with respect to the others
b) The red line is the best straight line that can be drawn,
for this the quality ajust is r²
the closer to 1 the better the fit
the equation of the line is
y = 1.06 x + 0.14
r² = 0.95
