Answer:
a = 3,0 m/s²
Explanation:
En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.
v= v₀ + a t
como el corredor parte del reposo si velocidad inicial es cero
v = at
a = v/t
calculemos
a = 12 /4,0
a = 3,0 m/s²
The final velocity of the red barge in the collision elastic is 0.311 m/s when it collides with blue barge pf mass 1000000 kg.
Final velocity(v3) of the red barge is calculated by following formula
m1×v1+ m2×v2= (m1+m2)v3
Substituting the value of m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/s
150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3
37500+ 320000= 1150000×v3
357500= 1150000×v3
v3= 0.311 m/s
<h3>What is elastic collision velocity? </h3>
- The velocity of the target particle after a head-on elastic impact in which the projectile is significantly more massive than the target will be roughly double that of the projectile, but the projectile velocity will remain virtually unaltered.
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A then B, as everything is made of energy and energy pushes the electro magnetic waves into the brain.
<span>The correct answer is D) 12 protons and no electrons. This is correct because the number of protons in the nucleus of the atom is 12. The number of protons in the nucleus represents the atomic number. Therefore if there are 12 protons in the nucleus, the atomic number is 12.</span>
For a distant astronomical object (a quasar) is moving away from us at half the speed of light, the speed of the light we receive from this quasar is mathematically given as c = 3x108 m/s
<h3>What is the
speed of light?</h3>
Generally, the equation for the is mathematically given as
The speed of light can be said to be measured to be approximately the value c = 3x108 m/s
.
In conclusion, An will not influence 3x108 m/s unless both are inertia and frames refrences where newtons laws are valid, so the speed of light measured from the earth frame is equal to 3x108 m/s
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