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Drupady [299]
3 years ago
7

At resonance, what is impedance of a series RLC circuit?

Physics
1 answer:
Elis [28]3 years ago
3 0

Answer:

c) Equal to R

b) the width of the resonance

Explanation: In general the impedance Z of an electrc circuit is:

Z = R + jX

Now when the circuit is capacitive, the above mentioned relation become  Z = R + 1/jwc  where ( w = 2πf  )

And when the circuit is inductive Z becomes

Z  =  R + j wl

Resonance  condition implies that the reactance created by capacitors are equal at the inductances produced by inductors, in other words the circuit will behaves as it were resistive.

The impedance will be equal to R

The Q factor is[

Q = X/R  in which X is the module of either the capacitive or inductive reactance.

Q has an inverse relation with the band width.  

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Susan, driving north at 53 mphmph , and Shawn, driving east at 63 mphmph , are approaching an intersection. Part A What is Shawn
mafiozo [28]

Answer:

Shawn's speed relative to Susan's speed = 10 mph

Resultant velocity = 82.32 mph

Explanation:

The given data :-

i) Susan driving in north and speed of Susan is ( v₁ ) = 53 mph.

ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.

iii) The speed of both Susan and Shawn is relative to earth.

iv) The angle between Susan in north and Shawn in east is 90°.

We have to find Shawn's speed relative to Susan's speed.

v₂₁ = v₂ - v₁   = 63 - 53 = 10 mph

Resultant velocity,

v = \sqrt{v_{2} ^{2}+ v_{1} ^{2}  }  =\sqrt{63^{2} +53^{2} }

v = 82.32 mph

5 0
3 years ago
PLEASE HELP
Gennadij [26K]

Answer:

3.675 m

Explanation:

a_{x} =0 v_{xo}=100 a_{y} =-g  v_{yo}=0

X-direction     | Y-direction

R=x_{o}+ v_{xo} t  | y=y_{o}+v_{yo}t+\frac{1}{2}a_{y}t^2

75=100t         |y=0+0+\frac{1}{2} (9.8)(0.75)

\frac{75}{100} =t             | y=3.675 m

0.75s=t              

Hope it helps

3 0
3 years ago
You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a
Sonja [21]

Answer:

L=55.9m

Explanation:

The equation for the period of a simple pendulum is:

T=2\pi\sqrt{\frac{L}{g}}

In our case what we know is the period and the acceleration of gravity, and we need to know the length of the pendulum, so we can write:

L=(\frac{T}{2\pi})^2g

Which for our values is:

L=(\frac{15s}{2\pi})^2(9.81m/s^2)=55.9m

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Oxana [17]

Answer:

the answer is  covalent bond

Explanation:

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