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4 years ago

At resonance, what is impedance of a series RLC circuit?

Physics

1 answer:

Elis [28]4 years ago

3 0

Answer:

c) Equal to R

b) the width of the resonance

Explanation: In general the impedance Z of an electrc circuit is:

Z = R + jX

Now when the circuit is capacitive, the above mentioned relation become Z = R + 1/jwc where ( w = 2πf )

And when the circuit is inductive Z becomes

Z = R + j wl

Resonance condition implies that the reactance created by capacitors are equal at the inductances produced by inductors, in other words the circuit will behaves as it were resistive.

The impedance will be equal to R

The Q factor is[

Q = X/R in which X is the module of either the capacitive or inductive reactance.

Q has an inverse relation with the band width.

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When a person's temperature reaches 104 degrees, the chances of survival are decreased dramatically. Group of answer choices Tru

Natali5045456 [20]

Answer:

True

Explanation:

With the increase in temperature hypothalamus fails and heatstroke occurs due to this failure. Hypothalamus is the region of our brain that act as a thermostat. It co-ordinates our physiological response to excessive heat. When the person’s temperature reaches to 104 degrees then it causes heatstroke. This heatstroke is very sudden and can kill person. Hence, we can conclude that when person’s temperature reaches to 104 degrees chances of survival decreases dramatically.

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4 years ago

A 50 kg boy and his 100 kg father went jogging. Both ran at a rate of 5m/s. Who had more kinetic energy

yanalaym [24]

The father because kinetic energy is calculated using 1/2mv^2, but in this case if the velocity was the same then the mass would affect the calculation, and the father has the greater mass this making him have the greater kinetic energy

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3 years ago

Two strings on a musical instrument are tuned to play at 196 hz (g) and 523 hz (c). (a) what are the first two overtones for eac

Tems11 [23]

(a) first two overtones for each string:
The first string has a fundamental frequency of 196 Hz. The n-th overtone corresponds to the (n+1)-th harmonic, which can be found by using
$f_n = n f_1$
where f1 is the fundamental frequency.

So, the first overtone (2nd harmonic) of the string is
$f_2 = 2 f_1 = 2 \cdot 196 Hz = 392 Hz$
while the second overtone (3rd harmonic) is
$f_3 = 3 f_1 = 3 \cdot 196 Hz = 588 Hz$

Similarly, for the second string with fundamental frequency $f_1 = 523 Hz$ , the first overtone is
$f_2 = 2 f_1 = 2 \cdot 523 Hz = 1046 Hz$
and the second overtone is
$f_3 = 3 f_1 = 3 \cdot 523 Hz = 1569 Hz$

(b) The fundamental frequency of a string is given by
$f= \frac{1}{2L} \sqrt{ \frac{T}{\mu} }$
where L is the string length, T the tension, and $\mu = m/L$ is the mass per unit of length. This part of the problem says that the tension T and the length L of the string are the same, while the masses are different (let's calle them $m_{196}$ , the mass of the string of frequency 196 Hz, and $m_{523}$ , the mass of the string of frequency 523 Hz.
The ratio between the fundamental frequencies of the two strings is therefore:
$\frac{523 Hz}{196 Hz} = \frac{ \frac{1}{2L} \sqrt{ \frac{T}{m_{523}/L} } }{\frac{1}{2L} \sqrt{ \frac{T}{m_{196}/L} }}$
and since L and T simplify in the equation, we can find the ratio between the two masses:
$\frac{m_{196}}{m_{523}}=( \frac{523 Hz}{196 Hz} )^2 = 7.1$

(c) Now the tension T and the mass per unit of length $\mu$ is the same for the strings, while the lengths are different (let's call them $L_{196}$ and $L_{523}$ ). Let's write again the ratio between the two fundamental frequencies
$\frac{523 Hz}{196 Hz}= \frac{ \frac{1}{2L_{523}} \sqrt{ \frac{T}{\mu} } }{\frac{1}{2L_{196}} \sqrt{ \frac{T}{\mu} }}$
And since T and $\mu$ simplify, we get the ratio between the two lengths:
$\frac{L_{196}}{L_{523}}= \frac{523 Hz}{196 Hz}=2.67$

(d) Now the masses m and the lenghts L are the same, while the tensions are different (let's call them $T_{196}$ and $T_{523}$ . Let's write again the ratio of the frequencies:
$\frac{523 Hz}{196 Hz}= \frac{ \frac{1}{2L} \sqrt{ \frac{T_{523}}{m/L} } }{\frac{1}{2L} \sqrt{ \frac{T_{196}}{m/L} }}$
Now m and L simplify, and we get the ratio between the two tensions:
$\frac{T_{196}}{T_{523}}=( \frac{196 Hz}{523 Hz} )^2=0.14$

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3 years ago

ariel has 2.6 grams of zinc . what volume of the material does she have if zinc had density of 7.13 g/cm

vaieri [72.5K]

Answer:

Ap. 4.6

Explanation:

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3 years ago

One way to improve food security is to avoid food spoilage. Identify the correct ways that Devon reduced food spoilage in the pa

quester [9]

The correct answer would be "He brought one serving to his neighbor's house, and stored the other two servings in the refrigerator. Devon ate one more serving or spaghetti the following day."

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4 years ago

Read 2 more answers