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alexgriva [62]
3 years ago
9

What impact would adding twice as much na2co3 than required for stoichiometric quantities have on the quantity of product produc

ed?
Chemistry
2 answers:
Veseljchak [2.6K]3 years ago
5 0

There would be no impact of adding twice as much {\mathbf{N}}{{\mathbf{a}}_{\mathbf{2}}}{\mathbf{C}}{{\mathbf{O}}_{\mathbf{3}}}  than required for stoichiometric quantities on the formation of the product.

Further explanation:

Stoichiometry of a reaction is used to determine the amount of species present in the reaction by the relationship between reactants and products. It is used to determine moles of a chemical species when moles of other chemical species present in reaction is given.

Consider the general reaction,

 {\text{A}}+2{\text{B}}\to3{\text{C}}

Here,

A and B are reactants.

C is the product.

One mole of A reacts with two moles of B to produce three moles of C. Stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.

The amount of reagents required for any chemical reaction depends on the stoichiometry of the reaction. If {\mathbf{N}}{{\mathbf{a}}_{\mathbf{2}}}{\mathbf{C}}{{\mathbf{O}}_{\mathbf{3}}}  is added twice the amount required according to the reaction stoichiometry, its excess amount will remain unreacted after the complete consumption of another reagent. It will not affect product formation. The quantity of products formed will vary if the concentration of all the reagents is altered.

Learn more:

1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: <u>brainly.com/question/3064603 </u>

2. Calculate the moles of ions in the solution: <u>brainly.com/question/5950133 </u>

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: Na2CO3, stoichiometry, reaction, no impact, product formation, twice, A, B, C, 2B, 3C, unreacted.

zubka84 [21]3 years ago
3 0
If too much of Na2Co3 is added to a particular chemical reaction, there will be a shortage of the other reactant which is supposed to react with the Na2Co3 and this will leads to excess production of the product. Stoichiometric should always be used to obtain information about the appropriate quantities of chemicals that should be used during chemical reactions. 
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URGENT !! A substance has 55.80% carbon, 7.04% Hydrogen, and 37.16% Oxygen. What is it's empirical and molecular formula if it h
Ede4ka [16]
<h3><u>Answer;</u></h3>

Empirical formula = C₂H₃O

Molecular formula = C₁₄H₂₁O₇

<h3><u>Explanation</u>;</h3>

Empirical formula

Moles of;

Carbon = 55.8 /12 = 4.65 moles

Hydrogen = 7.04/ 1 = 7.04 moles

Oxygen  = 37.16/ 16 = 2.3225 moles

We then get the mole ratio;

4.65/2.3225 = 2.0

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2.3225/2.3225 = 1.0

Therefore;

The empirical formula = <u>C₂H₃O</u>

Molecular formula;

(C2H3O)n = 301.35 g

(12 ×2 + 3× 1 + 16×1)n = 301.35

43n = 301.35

  n = 7

Therefore;

Molecular formula = (C2H3O)7

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4 years ago
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