Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W × 
/ ( 250 × π × 20 )
1300 × 
= (0.286)² × W × / ( 250 × π × 20 )
solve it and we get W
W = 249.56 × 
so elastic partial width is 2.49 eV
The nucleus of an atom is about 10-15 m in size; this means it is about 10-5 (or 1/100,000) of the size of the whole atom. A good comparison of the nucleus to the atom is like a pea in the middle of a racetrack. (10-15 m is typical for the smaller nuclei; larger ones go up to about 10 times that.)
Answer:
Explanation:
The average kinetic energy of molecules in a pot increases when it is heated on a stove . The heat energy is spent to decrease the intermolecular attractive force . The result is increase in kinetic energy due to increase in the velocity of molecules
formula for kinetic energy of one mole of a monoatomic gas
= 3/2 RT
when temperature increases , kinetic energy increases .
Answer: highly bouncy chick unchain Vicki bunch
Explanation:
Yk fr t tonight fine
Newton's 2nd law of motion . . . . . Force = (mass) x (acceleration)
Divide each side by (mass), and you have
Acceleration = (force) / (mass)
We know the force and mass for this truck, so we can fillum in:
Acceleration = (500 N) / (3,000 kg) = 0.167 m/s² .
