What energy changes take place in a glowing electric bulb

A steady electric current flows through a wire. If 9.0 C of charge passes a particular spot in the wire in a time period of 2.0

defon

1) Current: 4.5 A

2) Time taken: 4.7 s

Explanation:

1)

The electric current intensity is defined as the rate at which charge flows in a conductor; mathematically:

$I=\frac{q}{t}$

where

I is the current

q is the amount of charge passing a given point in a time t

For the wire in this problem, we have

q = 9.0 C is the amount of charge

t = 2.0 s is the time interval

Solving for I, we find the current:

$I=\frac{9.0}{2.0}=4.5 A$

2)

To solve this problem, we can use again the same formula

$I=\frac{q}{t}$

where

I is the current

q is the amount of charge passing a given point in a time t

In this problem, we have:

I = 3.0 A (current)

q = 14.0 C (charge)

Therefore, the time taken for the charge to move past a particular spot in the wire is

$t=\frac{q}{I}=\frac{14.0}{3.0}=4.7 s$

Learn more about electric current:

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8 0

3 years ago

A gas is compressed from an initial volume of 5.75 L to a final volume of 1.23 L by an external pressure of 1.00 atm. During the

nataly862011 [7]

Answer:

The internal energy change is 330.01 J

Explanation:

Given

$v_{1}$ the initial volume = 5.75 L

$v_{2}$ the final volume = 1.23 L

$P_{e}$ is the external pressure = 1.00 atm

q the heat energy removed = -128 J (since is removed from the system)

expansion against a constant external pressure is an example of an irreversible pathway, here pressure in is greater than pressure out and can be obtained thus;

W = - $P_{e}$ ΔV

W = -1.00 x(1.23 - 5.75)

W = -1.00 x -4.52

W = 4.52 L atm

converting to joules we have

W = 4.52 L atm x 101.33 J/ L atm = 458.01 J

The internal energy change during compression can be calculated thus;

ΔU = q + W

ΔU = -128 J + 458.01 J

ΔU = 330.01 J

Therefore the internal energy change is 330.01 J

8 0

2 years ago

[OU.04] The picture below shows two galaxies. What of these statements best describes a similarity between the two galaxies?

Vitek1552 [10]

Answer:

D.

Explanation: Both have shapes determined by gravitational forces.

7 0

2 years ago

Read 2 more answers

What is the voltage of this circuit.

liberstina [14]

Answer:

110.4 v

Explanation:

Find the equivalent resistance of the two parallel circuits

R1 and R2 in parallel = R1 * R2 / (R1+ R2) = 1 ohm

similarly R4 and R5 = 4.77 ohms

Now you can add the three resistances into one (R3=10)

1 ohm + 10 ohm + 4.77 ohm = 15.77 ohms

Now

V = IR

V = 7 amps * 15.77 ohm = 110.4 v

6 0

2 years ago

A householder has a 10.8 kW electric shower installed in the bathroom. Calculate the current drawn from the mains electricity su

emmasim [6.3K]

Answer:

90 A

Explanation:

Applying,

P = VI.............. Equation 1

Where P = Power, V = Supply voltage, I = current.

Make I the subject of the equation

I = P/V.............. Equation 2

From the question,

Assuming the Voltage of the main electric supply is 120 V

Given: P = 10.8 kW = 10800 W, V = 120 V (household voltage)

Substitute these values into equation 2

I = 10800/120

I = 90 A

5 0

3 years ago

What energy changes take place in a glowing electric bulb​

What energy changes take place in a glowing electric bulb