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boyakko [2]
4 years ago
10

Which two phrases describe a situation that will cause an object moving at a

Physics
1 answer:
notsponge [240]4 years ago
4 0

Answer:

The phrases the describe the situation are A and C

Explanation:

1- If a car is at rest or uniform motion, it will remain in that condition until an external force acts on it. If the external forces acting on a body are balanced , it means that their sum is equals to 0, which eventually results that no Net force is acting on it.

For balance forces, ∑F = 0

2- If the car moving at a constant speed is slowing down, it means that the forces have become unbalanced, eventually resulting in a Net force in the opposite direction of the motion of the car, due to which it is slowing down

For unbalanced forces, ∑F ≠ 0

The question satisfies 2, which is the answer

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How much WATER needed to offset the force of jumping down from 20metre in vacuum environment,to keep me alive.
kenny6666 [7]

Answer:

it's quite difficult

Explanation:

6 0
3 years ago
When Jane drives to work, she always places her purse on the passenger’s seat. By the time she gets to work, her purse has falle
madam [21]

Answer:

the vibrations push the purse up and down very fast and gravity pushes the purse down onto the floor

Explanation: does that help

7 0
4 years ago
Hey guys, I have a question about heat and stuff, and converting. THINK YOU COULD HELP?! THANKS!
Alexxandr [17]

Before answering this question it is necessary to know the conversion factors for temperatures.

<em>273 k = 0 ° C </em>

To transform a temperature from Kelvin to ° C we use the following Formula

T ° C = T Kelvin - 273

<u>For 373 K</u>

373K -273 = 100 ° C

<em>373 Kelvin equals 100° C. </em>

To transform a temperature from ° C to ° F we use the following formula:

(T° C x 9/5) + 32 = T ° F

Then:

<u>For 0 ° C </u>

(0° C x 9/5) +32 = 32 ° F

<em>0° C equals 32 ° F. </em>

<u>For 100° C </u>

(100 ° C x 9/5) +32 = 212 F

<em>100 ° C equals 212 ° F. </em>

Therefore, the correct option is the first:

373 Kelvin = 100 ° C = 212 ° F

4 0
3 years ago
Angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes (the):
Vsevolod [243]

Angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle

<h3>What is the line focus principle?</h3>

The line focus principle states that as the anode angle is reduced, the actual focal spot also becomes small but the heat loading is increased.

It also explains the relationship between the anode surface and the effective focal spot size.

As a result of this, by angling the target, effective area of the target is made much smaller that the actual area of electron interaction.

Hence, angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle.

Learn more about line focus principle here:

#SPJ1

3 0
2 years ago
The electric field everywhere on the surface of a thin, spherical shell of radius 0.725 m is of magnitude 899 N/C and points rad
Igoryamba

Answer:

Q = -52.56 nC

Explanation:

The electric field outside a spherical shell is given by

E = \frac{k*Q}{r^{2} }

where:

Q is the net  charge

r is the radius of the spherical shell and E is the electric field magnitude.

Given:

r = 0.725 m

since the field points radially toward the center of the sphere, E = -899 N/C.

k is a constant with a value = 8.99 x 109 Nm²/C².

∴-899  = \frac{8.99*10^{9} *Q}{0.725^{2}  }

Q  = \frac{-899*0.725^{2}  }{8.99*10^{9} }=-5.256*10^{-8}

Q = -52.56 nC

8 0
3 years ago
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