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3 years ago

Calculate the acceleration of a 3000 kg truck that had a net force of 500 N applied to it. Express your answer in m/s^2???

1 answer:

6 0

Newton's 2nd law of motion . . . . . Force = (mass) x (acceleration)

Divide each side by (mass), and you have

Acceleration = (force) / (mass)

We know the force and mass for this truck, so we can fillum in:

Acceleration = (500 N) / (3,000 kg) = 0.167 m/s² .

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Lyrx [107]

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3 years ago

Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face

Sunny_sXe [5.5K]

Answer:

$\mu = 1.645$

Explanation:

By Snell's law we know at the left surface

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now we have

$1 sin19 = \mu sin\theta_r$

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now on the other surface we know that

angle of incidence = $\theta_r'$

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so again we have

$\mu sin\theta_r' = 1 sin90$

so we have

$\theta_r = sin^{-1}\frac{0.33}{\mu}$

$\theta_r' = sin^{-1}\frac{1}{\mu}$

also we know that

$\theta_r + \theta_r' = 49$

$sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49$

By solving above equation we have

$\mu = 1.645$

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