3 years ago

Calculate the acceleration of a 3000 kg truck that had a net force of 500 N applied to it. Express your answer in m/s^2???

1 answer:

6 0

Newton's 2nd law of motion . . . . . Force = (mass) x (acceleration)

Divide each side by (mass), and you have

Acceleration = (force) / (mass)

We know the force and mass for this truck, so we can fillum in:

Acceleration = (500 N) / (3,000 kg) = 0.167 m/s² .

You might be interested in

Which vector best represents the net force acting on the +3 C charge

adelina 88 [10]

Vector ' W ' best and there ya go

7 0

3 years ago

How can density be determined in a lab of a rectangular solid?

True [87]

We will first record its mass and then its volume by measuring its dimensions
then divide mass by volume and will get density of regular solid

6 0

3 years ago

Lilit [14]

Endoskeleton- an internal skeleton, such as the bony or cartilaginous skeleton of vertebrates.

Exoskeleton- a rigid external covering for the body in some invertebrates animals, especially Arthropods, providing both support and protection.

8 0

4 years ago

Read 2 more answers

an 1150kg elevator moving down speeds up at a rate of 3.5m/s. what is the tension in the supporting cables?

gtnhenbr [62]

Answer:

The tension force in the supporting cables is 7245N

Explanation:

There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:

$F_{net} = F_g - F = m\cdot g - F\\$

We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:

$1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N$

The tension force F in the supporting cables is 7245N

3 0

3 years ago

A 75 kg astronaut floating in space throws a 5 kg rock at 5 m/sec. How fast does the astronaut move backwards?

JulijaS [17]

Answer:

The astronaut will get a velocity 0.064ms−1 opposite to the direction of the object.

4 0

2 years ago