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mestny [16]
4 years ago
12

What is the maximum efficiency of a heat engine whose operating temperatures are 590 ?c and 325 ?c?

Physics
1 answer:
mina [271]4 years ago
7 0
 <span>The maximum possible efficiency, i.e the efficiency of a Carnot engine , is give by the ratio of the absolute temperatures of hot and cold reservoir. 
η_max = 1 - (T_c/T_h) 

For this engine: 
η_max = 1 - [ (20 +273)K/(600 + 273)K ] = 0.66 = 66% 

The actual efficiency of the engine is 30%, i.e. 
η = 0.3 ∙ 0.664 = 0.20 = 20 % 

On the other hand thermal efficiency is defined as the ratio of work done to the amount of heat absorbed from hot reservoir: 
η = W/Q_h 

So the heat required from hot reservoir is: 
Q_h = W/η = 1000J / 0.20 = 5000J</span>
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H = mC_{ice} \Delta t\\\\H = mC_{ice}  (t_2 - t_1)\\\\1,000,000 = 2 \times 2090 \times (t_2 - (-90))\\\\1,000,000 = 4,180(t_2 +90)\\\\1,000,000 = 4,180t_2 + 376,200\\\\1,000,000 - 376,200 = 4,180t_2\\\\623,800 = 4,180 t_2\\\\t_2 = \frac{623,800}{4,180} \\\\t_2 = 149 \ ^0C

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