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VARVARA [1.3K]
2 years ago
5

What is the oscillation period of your eardrum when you are listening to the A4 note on a piano (frequency 440 Hz)?

Physics
2 answers:
Ulleksa [173]2 years ago
5 0

Answer:

<em>T </em>= 0.002 <em>s</em>.

Explanation:

Given data:

Frequency, f = 440 \ \rm Hz

The time period of oscillation of the eardrum can be expressed as,

T = \frac{1}{f}

T = \frac{1}{440 \ \rm Hz}

T = 0.002 \ s.

Contact [7]2 years ago
4 0

The period is the inverse of the frequence:

T=\dfrac{1}{f}=\dfrac{1}{440}=0.0022\overline{72}

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\blue{\bold{\underline{\underline{Answer:}}}}

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\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline{\bold{Given :}}} \\  \tt: \implies Constant \: force(F) = 8 \: N \\  \\ \tt: \implies Displacement(s) = 3 \: m \\  \\ \red{\underline{\bold{To \: Find : }}} \\  \tt:  \implies Work \: Done(W.D) = ?

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\green{ \star} \tt \:  \theta \:  = 0 \degree \:  \:  \:  \: (Angle \: between \: force \: and \: displacement) \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies Work \: Done = FS \: cos  \: \theta \\  \\  \tt:  \implies Work \: Done = 8 \times 3 \times cos \:0 \degree \\  \\ \green{ \circ} \tt \: cos  \: 0 \degree = 1  \\  \\  \tt:  \implies Work \: Done =24 \times 1 \\  \\   \green{\tt:  \implies Work \: Done =24 \: J}

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