All categories

2 years ago

How is the concept of wind best described?

Physics

2 answers:

konstantin123 [22]2 years ago

3 0

I believe that it is the first one just a guess tho. So don't trust me, just in case

Hunter-Best [27]2 years ago

3 0

The actual answer is the horizontal movement of air. I just took the test and got it wrong anf this showed up as the right answer. You can actually trust me.

Hope this helps :)

You might be interested in

45. A particle moves in a straight line with an initial velocity of 30 m/s and constant acceleration 30 m/s2 . (a) What is its d

omeli [17]

Answer:

Displacement after 5 seconds is 155/2 meters

Explanation:

Let X (t) represent the equation of the position, then you have to d2x / dt2 = 5.

Applying the fundamental theorem of the calculation dx/dt = 5t + vo. The speed equation is V (t) = 5t + vo. Since the initial velocity is 30m/s, V (0) = 5 (0) + vo = 30. Therefore, V (t) = dx/dt = 5t + 30. Applying again the fundamental theorem of the calculation X (t) = 5t^2 / 2 + 30t + xo.

Displacement in 5 seconds is given by X (5) - X (0).

X (5) - X (0) = 5 (5)^2/2 +3 (5) + Xo - 5 (0)^2/2 -3 (0) -Xo = 155/2

Displacement after 5 seconds is 155/2 meters

7 0

2 years ago

Read 2 more answers

A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it

vredina [299]

Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration

Using newton's second law

$F = ma$ ...(I)

Using formula of friction force

$F= \mu m g$ ....(II)

Put the value of F in the equation (II) from equation (I)

$ma=\mu mg$ ....(III)

$a = \mu g$

Put the value in the equation (III)

$a=0.24\times9.8$

$a=2.352\ m/s^2$

We need to calculate the distance,

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

$s=0+\dfrac{1}{2}2.352\times(3.0)^2$

$s=10.584\ m\ approx\ 11\ m$

Hence, The distance is 11 m.

3 0

2 years ago

You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont

Scilla [17]

Answer:

$R_{max} = 51.84 m$

Explanation:

When we shoot the dart upwards the time taken by the dart to go straight up and again come back is given as

$t = 4.6 s$

here we can say

$\Delta y = 0 = v_i t + \frac{1}{2}at^2$

$0 = v_i t - \frac{1}{2}(9.8)t^2$

put t = 4.6 s then we have

$v_i = 22.54 s$

Now in order to find the maximum range we can say

$R = \frac{v^2 sin2\theta}{g}$

so in order to have maximum range we can say

$\theta = 45 degree$

$R_{max} = \frac{v^2}{g}$

$R_{max} = \frac{22.54^2}{9.8}$

$R_{max} = 51.84 m$

5 0

2 years ago

Ms. Perry travels north 5 km, 10 Km west, and then turns and travels 5 Km 20 points

Lyrx [107]

Answer:

Explanation:

traveling north no displacement ,west displacement is 10,

4 0

2 years ago

The Ptolemaic theory of the universe was disproved by

GuDViN [60]

The Ptolemaic theory of the universe was disproved by Nicolaus Copernicus (1473–1543), letter C and followed by Johannes Kepler (1571–1630). Geocentric theory suggested that the Sun and moon orbited Earth, and the rest of the planets orbited the Sun is Heliocentric theory. Heliocentric theory of Nicolaus Copernicus during the Scientific Revolution on 17th and 18th century while Geocentric theory was proposed by Ptolemy (AD 150) and Aristotle. Today, we believe more on the Heliocentric theory and it has been proven as well.

8 0

3 years ago