Answer:
the wave represents the second harmonic.
Explanation:
Given;
length of the cord, L = 64 cm
The first harmonic of a cord fixed at both ends is given as;

The wavelength of a standing wave with two antinodes is calculated as follows;
L = N---> A -----> N    +   N ----> A -----> N
Where;
N is node
A is antinode
L = N---> A -----> N    +   N ----> A -----> N =  λ/2  + λ/2
L = λ
The harmonic is calculated as;

Therefore, the wave represents the second harmonic.
L = λ
 
        
             
        
        
        
Answer:
1626.4 N
Explanation:
Given that a 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him?
The parameters to be considered are:
Distance S = 3m
Time t = 0.55s
Since the man started from rest, initial velocity u = 0
Using second equation of motion 
S = Ut + 1/2at^2 
3 = 1/2 × a × 0.55^2
3 = 1/2 × a × 0.3025
a = 3/ 0.15125
a = 19.83 m/s^2
Force = mass × acceleration 
Force = 82 × 19.83
Force = 1626.4 N
Therefore, the force that water exerted on him is 1626.4 N
 
        
             
        
        
        
Answer:
The answer is 4x³ + 6x²
<u>-TheUnknownScientist</u><u> 72</u>
 
        
                    
             
        
        
        
C) alternating current .
<span>
B)direct current </span>
        
                    
             
        
        
        
The formula for force exerted on/by a spring is 
F = k*e where k is the spring constant and x is the distance stretched from
unstrained position. This should allow you to find what you need.
 
Using F = k x e, 
where k is the spring constant, 
and e is the extension, 
The F is her weight = 45 X 0.80 
= 36 N