Calculate the magnitude of the gravitational force
1 answer:
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Answer:
a) k = 200 N/m
b) E = 4 J
c) Δx = 6.3 cm
Explanation:
a)
- In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:
- where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).
- Solving for k:
b)
- Assuming no friction present, total mechanical energy mus keep constant.
- When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:
- Replacing k and Δx by their values, we get:
c)
- When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.
- We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).
- So, we can write the following expression:
- Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:
⇒
⇒
According to the planetary model, the speed of an electron revolving around the nucleus is given as follows;
v = e/√4∈₀mr.
The orbital speed of an electron, orbiting around a nucleus in a circular orbit of radius 50 consistent with the Bohr model, regularly called a planetary version, the electrons encircle the nucleus of the atom in precise allowable paths referred to as orbits. whilst the electron is in one of these orbits, its energy is fixed.
The ground nation of the hydrogen atom, wherein its electricity is lowest, is whilst the electron is inside the orbit that is closest to the nucleus. The orbits which can be similar to the nucleus are all of the successively extra power. The electron isn't allowed to occupy any of the areas in between the orbits. A regular analogy to the Bohr version is the rungs of a ladder pa is 2. 2×106ms−1.
Learn more about electrons here; brainly.com/question/12889606
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As it is given here that two blocks are pulled towards right side with constant horizontal velocity.
Both blocks are given that moving with speed 2 m/s
Now we can say that by Newton's II law
F = ma
i.e. Net force on a system is product of its mass and acceleration
but as we can see that here two blocks are moving with constant speed so here as per definition of acceleration we will say
As we know that v = constant
so here from 2nd law
so net force must be zero block A
So correct FBD must be "option A"
we should not represent any force on it