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vaieri [72.5K]
3 years ago
8

Explain How do the attractions between particles in a fluid determine viscosity?

Physics
1 answer:
Vikentia [17]3 years ago
6 0

Answer: Viscosity is due to particle mass, particle shape, and the strength of the attraction between the particles of a liquid. In general, the stronger the attractive forces between particles, the higher the viscosity. For many liquids, viscosity decreases when heat is applied.

Explanation:

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A teaspoonful of white dwarf material on earth would weigh
sashaice [31]

Answer:

15 tons

Explanation:

4 0
3 years ago
Arsenic diffusion in Si: Arsenic is diffused into a thick slice of silicon with no previous arsenic in it at 1100ºC. If the surf
Rainbow [258]

Answer:

Diffusion time is 7.42 h

Solution:

As per the question:

Temperature, T = 1100^{\circ}C

Surface concentration of arsenic, C_{S} = 5.0\times 10^{18}\ atoms/cm^{3}

Surface concentration below Silicon surface, C_{x} = 1.5\times 10^{16}\ atoms/cm^{3}

D = 3.0\times 10^{- 14}\ cm^{2}/s

x = 1.2\mu m = 1.2\times 10^{- 4}\ cm

Initial concentration at t = 0, C_{o} = 0

Now, by using Flick's second eqn:

\frac{C_{S} - C_{x}}{C_{x} - C_{o}} = erf(\frac{x}{\sqrt{Dt}})

Thus by putting appropriate values:

\frac{5.0\times 10^{18} - 1.5\times 10^{16}}{5.0\times 10^{18}} = erf(\frac{1.2\times 10^{- 4}}{2\sqrt{3.0\times 10^{- 14}t}})

0.997 = erf(\frac{364.4}{\sqrt{t}})              (1)

Now,

erf(z) = 0.997

Now, from error function values tabulation:

For z = 2.0, erf(z) = 0.998

For z = 2.2, erf(z) = 0.995

Now,

With the help of linear interpolation method:

\frac{z - 2}{2.2 - 2.0} = \frac{0.997 - 0.995}{0.998 - 0.995}

z = 2.12

Now, using eqn (1) and above value:

\frac{364.4}{\sqrt{t}} = 2.12

t = (\frac{364.4}{2.12})^{2} = 26700 s

t = \frac{26700}{3600} = 7.42\ h

7 0
3 years ago
If a substance has a pH of 10 -11, it is considered a ...
Mrac [35]

Answer:

Base

Explanation:

anything with a pH between 0-6 is an acid.  pH of 7 means neutral.  8-14 means it is a base

hope I helped :)

8 0
4 years ago
An athlete prepares to throw a 2.0-kilogram discus. His arm is 0.75 meters long. He spins around several times with the discus a
wlad13 [49]
Centripetal Force (Fcp) = ?

His arm length = Radius (R) = 0.75 m

Discus velocity = Linear Velocity (V) = 5 m/s

Discus mass (m) = 2 kg

Centripetal Acceleration (Acp) = V^2/R or W^2 x R
In this case i will use the V^2/R formula, because it uses the discus velocity (V).

fcp = m \times acp \\ fcp = m \times {v}^{2} \div r \\ fcp = 2 \times {5}^{2} \div 0.75 \\ fcp = 2 \times 25 \div 0.75 \\ fcp = 50 \div 0.75
fcp = 66.666... = 66 \: newtons

Answer: Last option, 66 N.
7 0
3 years ago
Read 2 more answers
Which of the following best describes force
Delicious77 [7]
B.a push or pull(which of the following best describes force)
4 0
4 years ago
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