Question

A car undergoing uniform acceleration travels 100 meters from a standing start in a given period of time. If the time were increased by a factor of four, calculate the displacement.

Answer 1

Answer:

d = 1600 m

Explanation:

If car start from rest and accelerates uniformly then the displacement of the car is given as

$d = v_i t + \frac{1}{2}at^2$

now we know

$d = 0 + \frac{1}{2}at^2$

now if the same car will accelerate from rest for four times of the previous time interval

then we will have

$d = 0 + \frac{1}{2}a(4t)^2$

$d = 16(\frac{1}{2}at^2)$

so the distance will be 16 times more

$d = 1600 m$